HIT HA12187FP Datasheet

HA12187FP
Bus Interface Driver/Receiver IC
ADE-207-174A (Z)
2nd Edition
Jun. 1999
Description
The HA12187FP was developed to be used as a bus interface driver/receiver IC in automotive audio equipment controllers. It implements a two-wire serial bus.
Two-input OR circuit
Input comparator circuit
Current output driver circuit
Receiver input comparator circuit
Receiver output circuit
Standby circuit
Features
Supports two data inputs (Pins 1 and 3 are the input pins)
Comparators with hysteresis characteristics were adopted for the inputs
Current drive output drivers adopted (Output current: 3.8 mA typical)
Comparators with hysteresis characteristics were adopted for the receivers
Wide receiver common-mode input operating range (Common-mode input operating range: 0 to 5 V
typical)
The driver output and the receiver input can withstand high voltages (Maximum rating: 18 V)
Standby function (The IC enters standby mode when pin 8 goes low)
Operating power-supply voltage range: 5 V ±0.5 V
HA12187FP
Block Diagram
S1
V
CC
7
1
3S2
+ –
Driver output
(current)
BUS (+)
6
8
2R
BIAS
Receiver
output
COM
5
BUS (–)
– +
4
Rev.2, Jun. 1999, page 2 of 23
Pin Functions
Pin No. Symbol Function Equivalent Circuit
1 S1 Data input
1
20 k
HA12187FP
2 R out Receiver output
3 S2 Data input
4GNDGND 5 BUS (–) Bus output (–) Receiver input (–) 6 BUS (+) Bus output (+) Receiver input (+)
7VCCPower supply 8 STB Standby control input
SW
SW
3
Receiver input (+)
Receiver input (–)
8
20 k
100 k
100
20k
SW
2
I
6
V
REF
5
I
Rev.2, Jun. 1999, page 3 of 23
HA12187FP
Absolute Maximum Ratings (Ta = 25°C)
Item Symbol Ratings Unit Notes
Power-supply voltage V Allowable power dissipation Pd 400 mW Ta 85°C Operating temperature Topr –40 to 85 °C Storage temperature Tstg –55 to 125 °C Input voltage Vin –1.0 to 6.7 V Bus input voltage Bus 18 V Note: Recommended operating power supply voltage range: 5 V ±0.5 V
CC
7V
Rev.2, Jun. 1999, page 4 of 23
HA12187FP
Electrical Characteristics (VCC = 5.0 V, Ta = 25°C)
Test
Test
Item Symbol Min Typ Max Unit Test Conditions
S1 High-level input
voltage
V
IHS1
3.5 V V1 = 0 V 5 V, V3 = 0 V With the potential difference between pin 5 and pin 6 120 mV or more
Low-level input voltage
V
ILS1
1.5 V V1 = 5 V 0 V, V3 = 0 V
With the potential difference between pin5 and pin 6 20 mV or less
High-level input
I
IHS1
1 µA V1 = 5 V, V3 = 0 V 1
current Low-level input
I
ILS1
1 µA V1 = 0 V, V3 = 0 V 1
current
S2 High-level input
voltage
V
IHS2
3.5 V V3 = 0 V 5 V, V1 = 0 V With the potential difference between pin 5 and pin 6 120 mV or more
Low-level input voltage
V
ILS2
1.5 V V3 = 5 V 0 V, V1 = 0 V
With the potential difference between 5 and pin 6 20 mV or less
High-level input
I
IHS2
1 µA V1 = 0 V, V3 = 5 V 3
current Low-level input
I
ILS2
1 µA V1 = 0 V, V3 = 0 V 3
current
Driver High-level
I
OH
3.0 3.8 4.8 mA IOH = | V
OHD+
– V
| / 62 5, 6 Figure 1
OHD–
output current Low-level output
leakage current Reference
I
OL
V
OP+
1 µA Pin 5 voltage = V
IOL = | V
OP+
– V
OP–
OP–
| / RI
2.3 2.5 2.7 V V1 = 0 V, V3 = 0 V 6
operating voltage (+)
Reference
V
OP–
2.3 2.5 2.7 V V1 = 0 V, V3 = 0 V 5
operating
voltage (–) Current drain 1 ICCH 5.5 7.3 9.5 mA V1 = 5 V, V3 = 0 V 7 Figure 1 Current drain 2 ICCL 1.7 2.2 2.7 mA V1 = 0 V, V3 = 0 V 7 Figure 1
Pin
Circuit
1 Figure 1
1
3 Figure 1
3
5, 6
Rev.2, Jun. 1999, page 5 of 23
HA12187FP
Electrical Characteristics (VCC = 5.0 V, Ta = 25°C) (cont)
Item Symbol Min Typ Max Unit Test Condition
Recei ver
Power supply off output leakage current
STB on voltage VSTBon — 1.5 V V8 = 5 0 V, V1 = 5 V, V8
STB off voltage VSTBoff 3.5 V V8 = 0 5 V, V1 = 5 V, V8
Standby mode current drain
Standby mode leakage current
Delay time (L H) DLY1 600 800 nS See the operating
Delay time (H L) DLY2 450 800 nS See the operating
Note: 1. I1 is the measured current when V6 = (V
High-level input
voltage (1)
Low-level input
voltage (1)
Input hysteresis
voltage (1)
High-level
common-mode
input voltage
Low-level
common-mode
input voltage
Receiver input
resistance*
1
High-level
output voltage
Low-level output
voltage
) – 0.3 V.
(V
OP+
V
IH1
80 120 mV V6 = 0 5 V, pin 2 = 4 V
or more, V1 = 0V, V3 = 0V, V5 = V
V
IL1
20 45 mV V6 = 5 0 V, pin 2 = 1 V
OP–
, V
IH1
= V6 – V5
or less, V1 = 0 V, V3 = 0 V,
V
V
IHYS1
IHCOM
V5 = V
10 35 60 mV V
IHYS1
= V
4.5 V V5 = 0 5 V, pin 2 = 4 V
OP–,VIL1
IH1
= V6 – V5
– V
IL1
or more, V1 = 0 V, V3 = 0 V, V6 – V5 = 120 mV
V
ILCOM
5 ——V V5 = 0 5 V, pin 2 = 1 V
or less, V1 = 0 V, V3 = 0 V, V6 – V5 = 20 mV
RI 25 35 45
V
V
I
OLEAK
OH
OL
4.5 V V1 = 5 V, V3 = 0 V 2 Figure 1
1.0 V V1 = 0 V, V3 = 0 V 2 Figure 1
——1 µAVCC off, V8 = 0 V, V6 = 5 V,
k
V1 = 0 V,
0.6V
=
RI
I1−I2
V1 = 0 V, V3 = 0 V, SW1 on
20 µA
CC
4.5 mA
CC
I
CCstb
when I
when I
10 20 µA V1 = 5 V, V3 = 0 V, V8 = 0V7 Figure 4
Istb-Leak — 1 µA V1 = 5 V, V3 = 0 V, V8 = 0
V, V6 = 5 V, SW1 on
waveform figure
waveform figure
) + 0.3 V, and I2 is the measured current when V6 =
OP+
Test
Test
Pin
Circuit
2 Figure 2
2 Figure 2
5 Figure 2
5 Figure 2
5, 6 Figure 3
5, 6 Figure 4
7 Figure 4
7 Figure 4
5, 6 Figure 4
2 Figure 5
2 Figure 5
Rev.2, Jun. 1999, page 6 of 23

Test Circuits

HA12187FP
V8
5 V
A
A
1
2
20 p
3
V1
V
47 k
V3
0 V
A 8
HA12187FP
4
0.1 µ
A 7
V
CC
5 V
6
V
62
5
V
Test Circuit 1
V8
5 V
8
20 p
1
2
3
HA12187FP
4
V1
0 V
V
47 k
V3
0 V
0.1 µ
7
V
CC
5 V
6
62
5
V6
V
V5
Test Circuit 2
V8
5 V
8
20 p
1
2
3
HA12187FP
4
V1
V
47 k
V3
0 V
0.1 µ
7
V
CC
5 V
6
5
A
62
V6
Test Circuit 3
Rev.2, Jun. 1999, page 7 of 23
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