SGS Thomson Microelectronics STPS3060CW Datasheet
STPS3060CW
POWER SCHOTTKY RECTIFIER
MAJORPRODUCTS CHARACTERISTICS
I
F(AV)
V
RRM
(max) 0.65 V
V
F
2 x15A
60 V
A1
K
A2
FEATURES AND BENEFITS
HIGHREVERSEVOLTAGE
NEGLIGIBLESWITCHINGLOSSES
LOWFORWARD VOLTAGE DROP
LOWTHERMAL RESISTANCE
A2
K
DESCRIPTION
Dual center tap schottky rectifier suited for
TO-247
A1
switchmodepower supply and high frequency DC
to DC converters.
Packaged in TO-247 this device is intended for
usein high frequency inverters.
ABSOLUTE RATINGS(limitingvalues)
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
I
FSM
Repetitivepeak reversevoltage
RMSforwardcurrent Per diode
Averageforwardcurrent Tc= 125°C
Surgenon repetitiveforward
current
I
RRM
T
stg
Tj
dV/dt
July 1998 - Ed: 2
Peakrepetitivereverse current tp = 2µs
Storagetemperaturerange
Maximumjunction temperature
Critical rate of risereversevoltage
δ =0.5
tp = 10ms
Sinusoidal
F = 1kHz
Per diode
Perdevice
Perdiode
Perdiode
60 V
30 A
15
A
30
200 A
1A
- 65 to +150 °C
150
10000 V/µs
1/4
STPS3060CW
THERMAL RESISTANCES
Symbol Parameter Value Unit
R
th(j-c)
Junctiontocase Perdiode
total 0.9
R
th(c)
Coupling 0.15 °C/W
Whenthe diodes1 and 2 are used simultaneously:
(diode 1) = P(diode1)x Rth(Perdiode)+ P(diode 2) x R
∆ T
J
th(c)
ELECTRICAL CHARACTERISTICS
STATIC CHARACTERISTICSPER DIODE
Symbol Parameter TestsConditions Min. Typ. Max. Unit
1.6 °C/W
*
I
R
V
F
Reverseleakage
current
**
Forwardvoltage drop Tj= 25°CI
Tj= 25°CV
Tj= 125°C
Tj= 125°CI
Tj= 125°CI
Pulse test : * tp = 5 ms,δ<2%
** tp = 380 µs, δ <2%
To evaluate the conductionlosses use the following equation:
P = 0.56 xI
F(AV)
+ 0.0113 I
F2(RMS)
Fig. 1: Average forward power dissipation versus
averageforwardcurrent (per diode).
PF(av)(W)
16
14
12
10
8
6
4
2
0
0 2 4 6 8 10 12 14 16
δ= 0.05
δ = 0.1
IF(av) (A)
δ = 0.2
δ = 0.5
=tp/T
δ
δ =1
T
tp
R=VRRM
30 µA
525mA
=20A
F
=20A
F
=10A
F
0.58 0.65
0.96 V
0.8
Fig. 2: Average current versus ambient
temperature(δ = 0.5) (per diode).
IF(av)(A)
16
14
12
10
8
6
4
2
0
0 25 50 75 100 125 150
δ
T
=tp/T
Rth(j-a)=15°C/W
tp
Rth(j-a)=Rth(j-c)
Tamb(°C)
2/4
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