*Please note that some calculator models cannot be used for certain activities.
*Operational procedures may differ depending on the calculator model you use.
Negative Value Calculations
Example
Example
Operation
(–3) × (–7) = ?
1. Enter the COMP Mode.
F 1
2. Perform the calculation (–3) × (–7).
D 3 - D 7=
Result: 21
– 1 –
Expression Values and Calculations
Example
Example
Operation
Determine the value of x2 –
1. Enter the COMP Mode.
F 1
2. Assign 5 to variable X.
5AJx
3. Assign –3 to variable Y.
D 3AJy
2
2
4. Determine the value of X
–
Y.
5
px K , 2C 5py =
Result: 26
1
5
2
y when x = 5 and y = –3.
5
– 2 –
Proportion and Inverse Proportion
y
x
–5
–5
5
5
–10
–10
10
10
Example
Example
For y = 12/x, calculate the values of y for x = 1, 2,
3, 4, 5, 6, to determine how the value of
in proportion to a gradual increase in the value of
x.
Next, calculate the values of
–4, –5, –6, to determine how the value of
changes in proportion to a gradual decrease in
the value of x.
Operation
y for x = –1, –2, –3,
1. Enter the COMP Mode.
F 1
2. Determine the value of y when x = 1.
y changes
y
1a - 12=
Result: 12
3. Determine the value of y when x = 2.
2a - 12=
Result: 6
4. Likewise, determine the values of y for x = 3, 4, 5, 6.
5. Press the [ key five times to display the value of y = 12 when x = 1.
– 3 –
Proportion and Inverse Proportion
6. Use the ] key to scroll through the values of y for x = 2, 3, 4, 5, 6.
The above reveals that the value of y decreases as the value of x increases.
7. Repeat steps 2 through 6 to calculate the values of y for x = –1 through –6.
○○○
Doing so will reveal that the value of y increases as the value of x decreases.
– 4 –
Circles and Sectors
Example 1
Example 1
Determine, up to one decimal place, the circumference and
the area of a circle with a radius of 8 cm.
l
Explanation
Explanation
Circumference of a circle: l = 2πr
Area of a circle: S = πr
(Radius = r)
2
r
Operation
1. Enter the COMP Mode.
F 1
2. Press the F key a number of times until 1 (Fix1) is specified as the fixed number of decimal
places.
F
• • •
1(Fix)1
]
3. Calculate the circumference of the circle.
2Ax - 8=
FIX
Result: 50.3
The circumference of the circle is approximately 50.3 cm.
4. Calculate the area.
A x - 8 K =
Result: 201.1
The area is approximately 201.1 cm2.
– 5 –
FIX
Circles and Sectors
Example 2
Example 2
Explanation
Explanation
Length of the arc of a sector: l = 2πr ×
Area of a sector: S = πr
(Radius = r, central angle = a°)
Operation
Determine, up to one decimal place, the length of the arc
and area of a sector that has a radius of 6 cm and a
central angle of 240°.
a
a
2
×
360
360
240°
6 cm
1. Enter the COMP Mode.
F 1
2. Press the F key a number of times until degrees (Deg) are specified as the angle unit.
F
• • •
1(Deg)
]
3. Press the F key a number of times until 1 (Fix1) is specified as the fixed number of decimal
places.
F
• • •
1(Fix)1
]
4. Determine the length of the arc of the sector.
2 A x - 6 - R 240 \ 360 T =
The length of the arc of the sector is approximately 25.1 cm.
5. Calculate the area.
A x - 6 K - R 240 \ 360 T =
The area is approximately 75.4 cm2.
FIX
FIX
– 6 –
Square Roots
Example 1
Example 1
Explanation
Explanation
Operation
Calculate the approximate square root values and then
compare the results.
Arrange the following from smallest to largest.
7, 2.7, 22/3, 18/7
1. Enter the COMP Mode.
F 1
2. Determine the approximate value of 7.
L7=
Result: 7 2.645751311]
3. Determine the approximate value of 22/3.
LR 22 \ 3 T=
Result: 22/3 2.708012802
4. Convert 18/7 to its decimal equivalent.
18 \ 7 =
Result: 18/7 = 2.571428571
5. Using the [ key to scroll through and compare the results produced by steps 2 through 4
reveals that the proper ascending order arrangement of the values is: 18/7 < 7 < 2.7 < 22/3.
– 7 –
Square Roots
Example 2
Example 2
Explanation
Explanation
• First, determine the area of the circle.
• If the length of one side of a square is l, the area of the
square is l2. This means that the length of one side of a
square with the same area as the above circle can be
determined by calculating the square root of the area.
Operation
Determine the length of one side of a square whose area is
equal to that of a circle with a radius of 10 cm.
1. Enter the COMP Mode.
F 1
2. First, determine the area of the circle with a 10cm radius.
A x - 10 K =
Result: S = 314.1592654
l
r
SS
=
3. Calculate the square root of the area.
L=
Result: l = S = 17.72453851
The above indicates that the length of one side of a square whose area is equal to that of a circle
with a radius of 10 cm is 17.7 cm.
– 8 –
Pythagorean Theorem
Example
Example
Explanation
Explanation
2
a
+ b2 = c
(Two sides = a, b; Hypotenuse = c)
2
Determine the length of the
hypotenuse of a right triangle whose
sides are 9 cm and 12 cm long.
Operation
1. Enter the COMP Mode.
F 1
2. Determine the sum of the squares of the two sides of the right triangle.
9K+12K= ]
3. Calculate the square root.
b
c
a
L=
Result: 225 = 15
The above shows that the length of the hypotenuse is 15 cm.
– 9 –
Permutation, Combination
Example 1
Example 1
What would be the maximum number of
different flag signals possible using eight
flags of eight different colors, when each
signal consists of three flags?
Explanation
Explanation
Determine 8P3.
Operation
1. Enter the COMP Mode.
F 1
2. Determine
8Am3=
Result: 8P3 = 336 ]
8P3
.
8
?
3
The above indicates there are 336 different signals possible.
– 10 –
Permutation, Combination
Example 2
Example 2
How many different combinations
are possible when selecting three
38
3
Explanation
Explanation
Determine 38C3.
individuals from a class of 38?
Operation
* The following shows operation using the fx-82MS/85MS/350MS/95MS.
1. Enter the COMP Mode.
F 1
2. Determine
38n3=
Result: 38C3 = 8436 ]
38C3
.
1
3
2
3
7
13
2
3
2
25
26
33
3238
5
4
6
5
4
3
27
6
5
4
6
5
4
6
29
28
30
35
34
36
1
1
3731
The above shows there are 8436 different combinations possible.
– 11 –
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