24
CHAPTER 3 ● General Technical Considerations
2. Example Heat Recovery Calculation
(1) Setting of conditions
(Note: Tokyo Power, industrial power 6 kV supply)
●
Return air volume (RA) = 8,000 m3/Hr
●
Outdoor air volume (OA) = 8,000 m3/Hr
●
Air volume ratio (RA/OA) = 1.0
●
Air conditions
(2) Selection of Lossnay model (select from treatment air volume catalogue)
●
Model name: LGH-100RX4 × 8 unit
●
Processing air volume per unit RA = 8,000 m3/Hr, OA = 8,000 m3/Hr, Air volume ratio (RA/OA) = 1.0
●
Heat recovery efficiency : Heat recovery efficiency = 79%, Enthalpy recovery efficiency (cooling) = 67%,
Enthalpy recovery efficiency (heating) = 71%
●
S
tatic pressure loss (unit-type) RA = 100 Pa, OA = 100 Pa (Note: Each motors are High notch)
●
Power consumption (pack-type) = 440W × 8 unit
= 3.52 kW
(3) State of indoor supply air
(4) Outdoor air load and heat recovered
(5) Recovered money (power rates)
Units When Heating When Cooling
Operation time (h/yr)
10h/day × 26 days/mo. × 5 mo./yr. = 1,300 h/yr 10h/day × 26 days/mo. × 4 mo./yr. = 1,040 h/yr
Electricity fee
(yen/kWh)
16.22 17.84
Capacity per
(kW/kW) 3.1 2.6
1 kW of electricity
Energy unit cost
(yen/kWh)
16.22/3.1 = 5.23 17.84/2.6 = 6.86
Season Winter heating Summer cooling
Item
Dry bulb temp
.Wet bulb temp.
Relative humidity
Absolute humidity
Enthalpy h Mark
Dry bulb temp.
Wet bulb temp.
Relative humidity
Absolute humidity
Enthalpy h Mark
DB [°C] WB [°C] RH [%]
× [kg/kg (DA)]
[kJ/kg (DA)]
in page 25 DB [°C] WB [°C] RH [%]
× [kg/kg (DA)]
[kJ/kg (DA)]
in page 25
Outdoors
0 –2.7 50 0.0018 4.7
1
33 27.1 63 0.0202
85.0 (20.3)
3
Indoors 20 13.8 50 0.0072 38.5
2
26 18.7 50 0.0105
53.0 (12.7)
4
Heating Cooling
= { 20 (Indoor temperature) – 0 (outdoor air temperature)} × = 33
(Outdoor air temperature) – { 33 (outdoor air temperature) –
Temperature [°C] 0.79 (heat recovery efficiency) + 0 (outdoor air temperature) 26 (indoor temperature)} × 0.79 (heat recovery efficiency)
= 15.8 = 27.5
Enthalpy
= {38.5 (Indoor enthalpy) – 4.7 (outdoor air enthalpy)} × = 85 (Outdoor air enthalpy) – { 85 (outdoor air enthalpy) –
[kJ/kg (DA)]
0.71 (enthalpy recovery efficiency) + 4.7(outdoor air enthalpy)
53
(indoor enthalpy)} × 0.67 (enthalpy recovery efficiency)
= 28.7 = 63.6
Numerical value obtained •Dry-bulb temperature = 15.8 °C •Wet-bulb temperature = 9.9 °C•Dry-bulb temperature = 27.5 °C •Wet-bulb temperature = 21.8 °C
from above equation and •Relative humidity = 46% •Absolute humidity = 0.005 kg/kg (DA)•Relative humidity = 61% •Absolute humidity = 0.014 kg/kg (DA)
psychometric chart•Enthalpy = 28.7 kJ/kg (DA) (page 25,
5
)
•
Enthalpy = 63.3 kJ/kg (DA) (page 25, 6)
Heating Cooling
Fresh air load without
= 1.2 (Air specific gravity) × 8,000 (outdoor air volume) × = 1.2 (Air specific gravity) × 8,000 (outdoor air volume) ×
Lossnay (q
1)
{ 38.5 (indoor enthalpy) – 4.7 (outdoor air enthalpy) } { 85.0 (outdoor air enthalpy) – 53.2 (indoor enthalpy) }
= 324,480 kJ/h = 90.1 kW = 307,200 kJ/h = 85.3 kW
= 90.1 (Outdoor air load) (q
1) × = 85.3 (Outdoor air load) (q1) ×
Outdoor air load with
{ 1 – 0.71 (enthalpy recovery efficiency)} { 1 – 0.67 (enthalpy recovery efficiency) }
Lossnay (q
2)
= 26.1kW = 28.2 kW
or or
=
Air specific gravity × outdoor air volume × (indoor enthalpy – indoor blow enthalpy)
=
Air specific gravity × outdoor air volume × (indoor enthalpy – indoor blow enthalpy)
= q1 – q2 = q1 – q2
= 90.1 - 26.1 = 85.3 - 28.2
Heat recovered (q
3)
= 64.0 kW = 57.1 kW
or or
= Outdoor air load (q1) × enthalpy recovery efficiency = Outdoor air load (q1) × enthalpy recovery efficiency
•
Outdoor air load = 90.1 kW = 100%
•
Outdoor air load =85.3 kW = 100%
Outdoor air load (%)•Outdoor air load with Lossnay = 26.1 kW = 29%
•
Outdoor air load with Lossnay = 28.2 kW = 33%
•
Heat recovered = 64.0 kW = 71%
•
Heat recovered = 57.1 kW = 67%
Heating Cooling
=
Heat recovered: kW ×Unit price yen/W ×operation time Hr/year = Heat recovered: kW × Unit price yen/W × operation time Hr/year
Yearly saved money = 64.0 kW × 5.23 yen/kWh × (1,300hr/year) = 57.1 kW × 6.86 yen × (1,040hr/year)
= 435,100 yen = 407,374 yen
Remarks If recovered heat is converted to electricity : heating = 64.0 kW/3.1 = 20.6 kW/h cooling = 57.1 kW/2.6 = 22.0 kW/h