F an Motor.................................................................................................................................................9
Run Capacitor .........................................................................................................................................10
System Control Switch ( "KS", "KM", & "KL" Models) ..............................................................................10
"KS" - "KM" Series Chassis Parts............................................................................................................20
"KS" - "KM" Series Cabinet Parts ............................................................................................................21
"KS" - "KM" Series Parts List...................................................................................................................20
"KL" Series Chassis Parts .......................................................................................................................25
"KL" Series Cabinet Parts........................................................................................................................26
"KL" Series Parts List ..............................................................................................................................25
Page 2
FRIEDRICH ROOM MODEL NUMBER CODE
1st DIGIT - FUNCTION
S = Straight Cool, Value Series
C = Straight Cool, Budget Series
Y = Heat Pump
E = Electric Strip
K = Straight Cool, Challenger or QuietMaster Series
W = Thru-The-Wall, WallMaster Series
2nd DIGIT - TYPE
C = Casement
P = Po werMiser “Portable”
Q = QStar, KStar or YQ TwinTemp
S = Small Chassis
M = Medium Chassis
L = Large Chassis
W = Built-In
H = Hazardgard
3rd & 4th DIGITS - APPROXIMATE BTU/HR (Cooling)
Heating BTU/HR capacity listed in Specifications/Perf ormance Data Section
KS10G10D
5th DIGIT - ALPHABETICAL MODIFIER
6th DIGIT - VOLTAGE
In the application and sizing of room air conditioners for cooling, it is most important to give full consideration to all
factors which may contrib ute to the heat loss or gain of the space to be conditioned. It is theref ore necessary to make
a survey of the space to be conditioned and calculate the load requirements before a selection of the size of the
equipment needed can be made.
The load requirement may be determined very easily by simply using the standard “AHAM” Load Calculating Form,
on Page 6. This form is very easy to use and is self explanatory throughout. It is necessary only to insert the proper
measurements on the lines provided and multiply by the given factors, then add the result f or the total load requirements.
Cooling load requirements are generally based on the cooling load for comfortable air conditioning which does not
require specific conditions of inside temperature and humidity. The load calculation form is based on outside design
temperature of 95° FDB and 75° FWB. It can be used f or areas in the Continental United States ha ving other outside
design temperatures by applying a correction factor for the particular locality as determined from the map shown on
Page 6.
When sizing a TwinTemp unit for cooling and heating, we must remember that the heating capacity of any given unit
varies directly with the outdoor ambient temperature. Also , we must keep in mind the av erage low temperatures which
might be experienced in the locality where the unit is to be installed. Therefore, when sizing a TwinTemp unit, both
cooling and heating requirements must be calculated. Do not ov ersize, or undersize , one phase of the unit’ s capacity
at the expense of the other. In those cases where the unit will provide satisfactory cooling at all times but will be
inadequate for those f e w times that the outdoor temperature is below the maxim um lo w f or the unit, additional auxiliary heating facilities must be provided to insure that adequate heat is av ailab le at all times.
Page 4
INSTRUCTIONS FOR USING COOLING LOAD ESTIMATE
FORM FOR ROOM AIR CONDITIONERS
(AHAM PUB. NO. RAC-1)
A.This cooling load estimate form is suitable for estimating the cooling load f or comfort air conditioning installations
which do not require specific conditions of inside temperature and humidity.
B.The form is based on an outside design temperature of 95°F dry bulb and 75°F wet bulb . It can be used for areas
in the continental United States having other outside design temperatures by applying a correction f actor for the
particular locality as determined from the map.
C.The f orm includes “day” f actors for calculating cooling loads in rooms where da ytime comf ort is desired (such as
living rooms, offices, etc.)
D .The numbers of the f ollo wing paragraphs refer to the corresponding numbered item on the form:
1.Multiply the square feet of window area for each e xposure by the applicab le f actor . The window area is the
area of the wall opening in which the window is installed. For windo ws shaded by inside shades or v enetian
blinds, use the factor for “Inside Shades.” For windows shaded by outside awnings or by both outside
awnings and inside shades (or venetian blinds), use the factor for “Outside Awnings.” “Single Glass” includes all types of single thickness windows, and “Double Glass” includes sealed airspace types, storm
windows, and glass bloc k. Only one number should be entered in the right hand column for Item 1, and this
number should represent only the exposure with the lar gest load.
2.Multiply the total square feet of all windows in the room b y the applicab le factor.
3a.Multiply the total length (linear feet) of all walls exposed to the outside b y the applicable f actor. Doors should
be considered as being part of the wall. Outside walls facing due north should be calculated separately
from outside walls facing other directions. Walls which are permanently shaded by adjacent structures
should be considered “Nor th Exposure.” Do not consider trees and shrubbery as providing permanent
shading. An uninsulated frame wall or a masonry wall 8 inches or less in thickness is considered “Light
Construction. ” An insulated wall or masonry wall over 8 inches in thic kness is considered “Hea vy Construction. ”
3b.Multiply the total length (linear feet) of all inside w alls between the space to be conditioned and any uncon-
ditioned spaces by the given f actor . Do not include inside walls which separate other air conditioned rooms.
4.Multiply the total square feet of roof or ceiling area by the factor given for the type of construction most
nearly describing the particular application (use one line only.)
5.Multiply the total square feet of floor area by the factor giv en. Disregard this item if the floor is directly on the
ground or over a basement.
6.Multiply the number of people who normally occupy the space to be air conditioned by the factor given. Use
a minimum of 2 people.
7.Determine the total number of watts for light and electrical equipment, except the air conditioner itself, that
will be in use when the room air conditioning is operating. Multiply the total wattage by the factor given.
8.Multiply the total width (linear feet) of any doors or arches which are continually open to an unconditioned
space by the applicable factor.
NOTE: Where the width of the doors or arches is more than 5 feet, the actual load may exceed the
calculated value. In such cases, both adjoining rooms should be considered as a single large room, and the
room air conditioner unit or units should be selected according to a calculation made on this new basis.
9.Total the loads estimated for the foregoing 8 items.
10.Multiply the subtotal obtained in item 9 by the proper correction factor, selected from the map, for the
particular locality . The result is the total estimated design cooling load in BTU per hour .
E.For best results, a room air conditioner unit or units ha ving a cooling capacity rating (determined in accordance
with the NEMA Standards Publication for Room Air Conditioners, CN 1-1960) as close as possible to the estimated load should be selected. In general, a greatly oversized unit which would operate intermittently will be
much less satisfactory than one which is slightly undersized and which would operate more nearly continuously .
F.Intermittent loads such as kitchen and laundry equipment are not included in this form.
Minimum Ext. Into Room3-1/16"3-1/16"3-1/16"3-1/16"3-3/16"3-3/16"
Minimum Ext. to Outside16-15/16"16-15/16"16-15/16"16-15/16"16-15/16"18-15/16"
Net Weight108111111136183190
Shipping Weight118121121148203210
PERFORMANCEEVAPORATOR AIROPERATINGELECTRICALR-22COMP.
DA TA*TEMP. °F.PRESSURESRATINGSREFRIG.OIL
CoolingDISCHARGETEMP.SUCTIONDISCHARGE AMPSLOCKEDCHARGE INCHARGE IN
* Rating Conditions:80°F. Room Air Temperature and 50% Relative Humidity with
95°F. Outside Air Temperature at 40% Relative Humidity.
5.8
6.2
8.3
9.1
10.5
11.3
13.5
15.0
Page 7
COMPONENTS OPERATION & TESTING
WARNING
DISCONNECT ELECTRICAL POWER TO
UNIT BEFORE SERVICING OR TESTING
COMPRESSORS
GROUND TEST
Use an ohmmeter set on its highest scale. Touch one
lead to the compressor body (clean point of contact as
a good connection is a must) and the other probe in
turn to each compressor ter minal (see Figure 2.) If a
reading is obtained, the compressor is grounded and
must be replaced.
Compressors are single phase, 15 or 230/208 volt, depending on the model unit. All compressor motors are
permanent split capacitor type using only a running capacitor across the start and run terminal.
All compressors are internally spring mounted and externally mounted on rubber isolators.
COMPRESSOR WINDING TEST (See Figure 1)
Remove compressor terminal box cover and disconnect
wires from terminals. Using an ohmmeter, check continuity across the following:
1. Terminal “C” and “S” - no continuity - open winding - replace compressor.
2. Terminal “C” and “R” - no continuity - open winding - replace compressor.
3. Terminal “R” and “S” - no continuity - open winding - replace compressor.
Figure 1:Compressor Winding Test
Figure 2:Typical Ground T est
CHECKING COMPRESSOR EFFICIENCY
The reason for compressor inefficiency is normally due
to broken or damaged suction and/or discharge valv es,
reducing the ability of the compressor to pump refrigerant gas.
This condition can be checked as follo ws:
1. Install a piercing valve on the suction and discharge or liquid process tube.
Page 8
2. Attach gauges to the high and low sides of the
system.
3. Star t the system and run a “cooling or heating
performance test.”
If test shows:
A. Below normal high side pressure.
B. Above normal low side pressure.
C. Low temperature difference across coil.
The compressor valves are faulty - replace the
compressor.
THERMAL OVERLOAD (External)
Some compressors are equipped with an external overload which is located in the compressor terminal box
adjacent to the compressor body (see Figure 3.)
The overload is wired in series with the common motor
terminal. The overload senses both major amperage and
compressor temperature. High motor temperature or
amperage heats the disc causing it to open and break
the circuit to the common motor terminal.
Figure 3: External Overload
Should the internal temperature and/or current draw become excessive, the contacts in the overload will open,
turning off the compressor. The overload will automatically reset, but may require se veral hours bef ore the heat
is dissipated.
CHECKING THE INTERNAL OVERLOAD
(see Figure 4.)
Figure 4
Heat generated within the compressor shell is usually
due to:
1. High amperage.
2. Low refrigerant charge.
3. Frequent recycling.
4. Dirty condenser.
THERMAL OVERLOAD - TEST
(Compressor - External Type)
1. Remove overload.
2. Allow time for overload to reset before attempting
to test.
3. Apply ohmmeter probes to terminals on overload
wires. There should be contin uity through the overload.
TERMINAL OVERLOAD (Internal)
Some model compressors are equipped with an internal overload. The overload is embedded in the motor
windings to sense the winding temperature and/or current draw. The overload is connected in series with the
common motor terminal.
1.With no power to unit, remove the leads from the
compressor terminals.
2.Using an ohmmeter, test continuity between terminals C-S and C-R. If not continuous, the compressor overload is open and the compressor must
be replaced.
FAN MOTOR
A single phase permanent split capacitor motor is used
to drive the ev apor ator blo wer and condenser f an.
A self-resetting overload is located inside the motor to protect against high temperature and high
amperage conditions.
FAN MOTOR - TEST
1.Determine that capacitor is serviceable.
2.Disconnect fan motor wires from fan speed switch
or system switch.
3.Apply “live” test cord probes on b lack wire and common terminal of capacitor. Motor should run at high
speed.
4.Apply “live” test cord probes on red wire and common terminal of capacitor. Motor should run at low
speed.
Page 9
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