Philips Semiconductors Linear Products Product specification
NE587LED decoder/driver
August 31, 1994
536
However, a major portion of this power dissipation (P
D MAX
) is
because the current source output is operating with 3.25V across it.
In practice, the outputs operate satisfactorily down to 0.5V , and so
the extra voltage may be dropped external to the integrated circuit.
Suppose the worst-case V
CC/VS
supply is 4.75 to 5.25V, and that
the maximum V
E
for the LED display is 2.25V. Only 2.75V is
required to keep the display active, and hence 2.0V may be dropped
externally with a resistor from V
CC
to VS. The value of this resistor is
calculated by:
R
S
+
2.0
7 x I
SEG
[ 10 (
1
2
W rating)
assuming worst case I
SEG
of 30mA.
Hence now
P
D MAX
= V
CC
× I
CC
+
(V
S
- V
V
- R
X
× 7 × I
SEG
) × 7 × I
SEG
× K
DC
= 5.25 × 50 + 1.25 × 7 × 30mW
= 525mW
and
P
D av
= 5.0 × 30 + 1.25 × 5 × 25 = 306 mW.
If a diode (or 2) is used to reduce voltage to the display, then the
voltage appearing across the display driver will be independent of
the number of “ON” segments and will be equal to
V
S
- V
F
- nVd, VD≈ 0.8V
Where n is the number of diodes used, power dissipation can be
calculated in a similar manner.
In a multiplexed display system, the voltage drop across the digit
driver must also be considered in computing device power
dissipation. It may even be an advantage to use a digit driver which
drops an appreciable voltage, rather than the saturating PNP
transistors shown in Figure 9. For example a Darlington PNP or
NPN emitter-follower may be preferable. Figure 8 shows the NE591
as the digit driver in a multiplexed display system. The NE591 output
drops about 1.8V which means that the power dissipation is evenly
distributed between the two integrated circuits.
Where V
S
and VCC are two different supplies, the VS supply may be
optimized for minimum system power dissipation and/or cost.
Clearly, good regulation in the V
S
supply is totally unnecessary, and
so this supply can be made much cheaper than the regulated 5V
supply used in the rest of the system. In fact, a simple unsmoothed
full-wave rectified sine wave works extremely well if a slight loss in
brightness can be tolerated. A transformer voltage of about
3-4.5V
RMS
works well in most LED display systems. Waveforms are
shown below:
V
S
I
SEG
The duty cycle for this system depends upon VS, VF and the output
characteristics of the display driver.
With
V
S
= 4.9V peak
V
F
= 2.0V
The duty cycle is approximately 60%.