• Detailed plan of building, construction of outer
walls, and size and type of windows.
These data are essential for calculation of the
heating load in accordance with EN 12831.
• Information on the type of ooring and its
thermal resistance R
dependent on the oor construction, particularly
, since the heat output is
λ,B
that over screed (in accordance with EN 1264 a
thermal resistance of R
living rooms is specied, in bathrooms R
m2 K/W. Other values up to a maximum of 0.15
m2 K/W are to be separately agreed.) R
m2 K/W.
= 0.1 m2 K/W R
λ,B
λ,B
for
λ,B
= 0.0
λ,B
= 0.0
• Building plans, building drawings and all room
data have to be shown. After the calculations,
the pipe layout and data are included in the
building plan.
• Danfoss forms for calculations.
The following standards have to be observed when
planning and installing oor heating:
EN 1991 Action on structures
EN 1264 Underoor Heating, Systems and
Components
Changes in building methods over the last few
decades have brought about lower requirements
for heating homes, so that Danfoss underoor
heating can meet respective heating requirements
for even physiologically acceptable surface temperatures. In some rooms, such as bathrooms,
additional heating may be necessary, as areas
under bath and shower cannot be heated and
a higher temperature is required (24° C instead
of 20° C). In such rooms the underoor heating
maintains the temperature in the oor while other
heat comes from sources such as wall heating,
heated towel rails, etc.
EN 13813 Screed Material and Floor Screeds
Local building regulations.
Professional information on interface
co-ordination when planning heated
underoor constructions (ref: BVF).
Estimated
pre-calculations
DIN 4109 Sound Insulation in the Building
Industry
ISO EN 140-8 Measurement of sound insulation
in buildings and building elements
The output tables of Danfoss SpeedUp and Basic
heating systems show output values for various
room temperatures as well as the temperatures of
the central heating water in relation to dierent
oor nishes. These tables give calculations of the
mean central heating water temperature with
which to run the underoor heating in order to
achieve the desired output.
EN 1264 is crucial for the construction of underoor heating. With the inclusion of EN 13813
‘Screed Material and Floor Screeds’ three Basic
Danfoss constructions are possible.
The required excess heat source temperature
determines the supply temperature which is
described in more detail in the chapter ‘Calculating
the supply Temperature’. The heat ow densities
are distributed evenly over the edge and comfort
zones. The main central heating water temperature is determined by the type of installation (see
output tables).
When making calculations for Danfoss underoor
heating the standard heat load Q
essential. For underoor heating in multi-storey
of the room is
N,f
buildings the heat gain of the shared oor can be
included into the calculations if there are no
restrictions on the work.
The heat output QH is generally calculated from
the standard heat load of an underoor heated
room Q
accordance with EN 4701 Part 3.
plus an extra calculation allowance in
H,f
QH = (1 + x)* Q
N,f
It is important to consider the thermal resistance
of the insulation below the underoor heating so
that the heat of the underoor heating radiates
mainly upwards.
In accordance with EN 1264, Part 4 there are three
dierent kinds of oor/storey constructions and
various minimum heat resistances.
Thermal InsulationR
A above rooms with similar use 0.75 m2 K / W
B above rooms with dierent
use*, unheated rooms (e.g.
cellar) and on ground oor
C above external air (-15°C) (e.g.
garages, passage ways)
* e.g. rooms above commercially used premises
1.25 m
2.00 m
Ins, min
2
2
K / W
K / W
Q
: Standard heating load of an underoor
N,f
heated room [W]
QH: Heat output calculation
If the heating system, such as an underoor
system, can raise the heat output by raising the
heat source temperature the extra allowance is is
zero. Thus the calculated temperature output
equals the standard heat load of an underoor
heated room.
The heat resistance R
layer is calculated as follows:
R
with a single insulation
λ.ins
S
=
λ,ins
λ
ins
ins
with:
S
: eective insulation thickness [m]
ins
λ
: thermal conductivity [W/m K]
ins
Maximum surface
temperature Θ
Fmax
Fluctuation in
temperature (W)
In accordance with EN 1264 maximum surface
temperatures for phsysiological reasons are set
as follows:
Comfort zone: 29° C
Edge zone: 35° C
Bathrooms: ti + 9° C = 33° C
Standard room temperatures of 20 or 24° C
in bathrooms result in a dierence in surface
The position of the heating pipe can further
inuence the output. Depending on the position,
varying surface temperatures can occur. Output
is higher above the pipes than in between. The
dierence between the maximum and minimum
surface temperatures is called uctuation (W).
W =θ
F max
- θ
F min
Larger distances between pipes cause larger
uctuation. Lower lying pipes slow down the heating
sy stem but the ‘ long w ay’ to the sur fac e dis tribu tes
the temperature evenly, the uctuation remains
small. Since the maximum oor temperature must
not be exceeded, larger uctuation causes greater
loss in output than a smaller uctuation. In the rst
temperature and room temperature of 9K (in
comfort zones and bathrooms) or 15K (in edge
zones). Limiting the surface temperature has
the eect of limiting the heat output of the
underoor heating. It is an important factor when
deciding whether to choose additional heating.
However, with modern insulation the heat output
in underoor heating is sucient in 99 of 100
cases.
case, average oor temperature is signicantly lower
than the maximum permitted temperature.
The Characteristic base line shows the relationship between the heat ow density and the
surface temperature (surface temperature minus
room temperature) when the heated area is
evenly heated (uctuation = 0).
Heat output q
Mean surface temperature difference
With a surface temperature of 9K above room
temperature an output of approx. 100W/m2 is
achieved, with an excess temperature of 15K a
heat output of approx. 175 W/m2.
Since the characteristic base line has idealised
physical parameters and is valid independent of
the system, no system, kept at the maximum
permitted surface temperature, can reach an
output of more than 100 W/m2 or 175 W/m2 in
edge zones.
Consequently the specic heat output q of the
oor surface depends on the dierence between
room and surface temperatures as well as the
transferability. The latter is dependent on the
room data, including the needs to air the room
and is described as heat transfer coecient α
here 11.1 W/m2K.
q =α
(θF - θi)
ges
ges
θF = Floor temperature °C
θi = Room temperature °C
Example:
At a room temperature of 20° C and a oor
temperature of 27° C a heat output of
q = 11.1 W/m2 K * 7°K (27° C - 20° C)
= 77.7 W/m2 would be achieved.
Heat source temperature
Installation types
The mean heat source temperature is a rm
component of many calculations. It is calculated
from the mean value of the supply and return
temperatures:
θm = θi + Δθ
H
The heating system Danfoss Basic comprises two
dierent installation types in edge zones and
three in comfort zone areas.
SystemPossible pipe distance in cm
BasicRail8.8 (mean)
BasicRail12 (mean)
BasicRail20
BasicRail25
BasicRail30
BasicGrip and BasicClip10
BasicGrip and BasicClip15
BasicGrip and BasicClip20
BasicGrip and BasicClip25
BasicGrip and BasicClip30
SpeedUp and SpeedUp Eco12.5
SpeedUp and SpeedUp Eco25
with:
ΔθH: Excess Heat Source Temperature
θi: Standard - Inside Temperature
θm: Heat Source Temperature
The SpeedUp and SpeedUp Eco heating systems
has installation types for the edge and comfort
zones. They dier in pipe distance.
The heat output and the uctuation of the surface
temperature are dependent on several factors:
• Floor surface temperature
• Room temperature
• Pipe distances
• Thickness and thermal conductivity of the
load bearing panels
• Lateral heat output
• Thermal resistance of oor nish
• Composition of the layers
In accordance with EN 1264 all factors combine
into the following equation heat ow density q:
q = KH + Δθ
H
with:
q: Heat output [W/m2]
KH: Equivalent heat transfer coecient [W/m2 K]
(ocial DIN check)
ΔθH: Excess heat source temperature
When doing the calculations for underoor
heating, the calculated heat ow density is to be
worked out as follows in accordance with DIN EN
1264, Part 3 :
Q
q
=
des
N,f
A
F
with:
q
Calculated heat ow density [W/m2]
des
Q
Standard-heat load of an underoor heated
N,f
room [W]
AF Floor area to be heated [m2]
The heat output achieved from underoor
heating is
QF = q * A
F
with:
Δθ
H
θ
- θ
=
V
R
- θ
θ
V
θR - θ
i
i
In
with:
θV: Supply temperature
θR: Return temperature
θi: Standard-inside temperature
When keeping to maximum permitted temperatures, the above factors will give, apart from
uctuation, limiting curves (calculated according
to EN 1264, Part 2). The intersections indicate the
heat ow limits and the limits to excess heat
source temperatures.
The data for the heat ow densities of the edge
zones or comfort zones qR and qA can be calculated from the output diagrams where the excess
temperature of the heat source applies.
The approved threshold of the heat ow density
(intersection of curves with limiting curve) must
not be exceeded. The approved density depends
on the thermal resistance of the oor covering
and the construction type.
If one value of the calculated and distributed heat
ow density (qR/qA) is above the threshold heat
ow density, the threshold density rather than the
heat ow density applies. The resulting decrease
in excess heat source temperature also reduces
the heat ow density of the other combination
type of installation.
If the standard heat load of a room heated with
underoor heating is greater than the heat output
of the underoor heating, additional heating for
the shortfall should be considered. Q
N,f
- QF.
with:
q
Calculated heat ow density
des
Q
Standard-heat load of an underoor heated
N,f
room
AF Floor area to be heated
where q is evenly distributed over the edge zone
(maximum 1 m wide) and the comfort zone:
The calculated supply temperature for a room
with the highest calculated heat ow density is
assigned q
thermal resistance for oor cover of R
K/W. Higher values for R
account. Bathrooms will have R
The dierential temperature σ for the room to be
(except bathrooms) and given a
max
have to be taken into
λ,B
λ,B
= 0.0 m2 K/W.
λ,B
= 0.10 m2
calculated is dened as σ = 5 K. The installation
type is chosen so that q max fully achieves the
threshold heat ow density indicated in the
limiting curve. The maximum permitted excess
ow temperature is
Δθ
V, des
≤ Δθ
when
H, des
+
σ
Δθ
σ
2
≤ 0.5:
H
with Δθ
H, des
≤ Δθ
H, G
otherwise:
Δθ
V, des
= Δθ
H, des
σ
+
+
2(12 Δθ
2
σ
)
H, des
In all other rooms which are operating on
calculated ow temperatures the dierential
temperature is calculated as follows, as long as
the relation:
σ
j
< 0.5
Δθ
H, j
is:
Δθ
: Excess heat source temperature of each room j
H,j
with:
σ j = 2 * [(Δθ
V, des
) – Δθ
]
H,j
otherwise:
4(Δθ
- Δθ
σ j = 3 * Δθ
*
H, j
[√
1+
V, des
3 * Δθ
)
H, j
-1
H, j
]
Calculation heat source
temperature
For calculating the size of the circulating pump
the mass ow rate is determined as mH (ow rate
of heating water in kg/s). It is independent of the
total output (oor heating output, and heat losses
to other rooms) as well as dierential temperature.
mH =
* q
A
F
σ * C
R
1 +
(
W
R
- θ
θ
o
i
q * R
u
)
u
+
u
with CW = 4190 J/kgK
The partial heat transfer resistance of the oor
construction Ro (upwards) encompasses both the
thermal conductivity and thermal resistance
upwards:
1
Ro =
with1= 0.093 m2 K/W
+ R
αλ
α
S
u
+
λ ,B
u
The sum of the downwards thermal conductivity
and downwards thermal resistances is:
Ru = R
λ, ins
with R
+ R
λ, oor
= 0.17 m2 K/W
α, oor
+ R
λ, render
+ R
α, oor
The mass ow rate mH can also be expressed
when converted as the ow rate VH:
m
VH =
with ρ = 0.998 kg/dm
H
ρ
3
To determine the ow rate of a heating circuit the
ow rate of the room VH must be divided by the
number of heating circuits:
For the calculations and size of the circulating
pump it is important to calculate pressure loss. In
order to calculate pressure loss the total length of
the pipes IHK and supply and returns have to be
determined. Here it is important that the length
of the supply and return pipes FEED is double the
distance of room to manifold (supply and return).
Depending on the laying type the following
values are relevant:
lH = Pipe length of edge zone layout plan * AR
+ Pipe length of comfort zone layout plan * A
The mean length of the heating circuit IHK is
calculated thus:
I
IHK = FEED +
Here it must be mentioned that the area layout
and the number of heating circuits are determined
by the type of screed, i.e. the heating circuits must
be compatible with the screed sections.
Number of heating circuits
(
H
A
)
The pressure loss diagram (cf. pressure loss
diagram for Danfoss composite pipe) shows, via
ow rate per heating circuit V
resistance as pressure loss Δp per m. To calculate
the total loss of a heating circuit, this value has to
be multiplied by the length of the heating circuit.
ΔpHK = Δp * l
Individual heating circuits have dierent lengths
and dierential temperatures and show dierent
loss of pressure. Pressure compensation ensures
that all heating circuits are supplied with
sucient water. The ow adjustment is made on
the return valve by determining the ow per
minute (i.e. the volume ow [l/h] of the individual
heating circuits is divided by 60 [min.]).
The total water volume within an underoor heating system is calculated by the length of all
heating circuits IHK multiplied by a factor of 0.113
(l/m).
, the pipe friction
HK
HK
Correlation between flow
rate, pressure loss and
differential temperature:
Threshold values
The smaller the dierential temperature:
• the higher the volume ow
• the higher the ow speed of the medium and
• the higher the pressure loss
• The maximum supply temperature must not
exceed 55° C for wet cement and calcium
sulphate (CAF) screed
• Heating circuits should not be longer than
100 m, 110 m maximum.
• The optimum length is 120 m.
• Pressure loss of 250 mbar must not be
exceeded since the circulating pump, apart
from maintaining the pressure head, has to
cope with pressure losses in the heating
circuits and in the whole system (in manifold,
its valves, supply and return pipes, mixing
valves, etc.).
• The maximum supply must not exceed 50° C
for gypsum plaster.
Raising the dierential temperature causes a
reduction in ow rate.
Quick and easy dimensioning of the floor heating system
The proper dimensions for oor heating systems
can be calculated in a matter of minutes by using
the Internet-based Danfoss Floor Heating
Dimensioning Programme.
With a few, basic inputs, this easy-to-use software
will provide all the necessary information regarding
system design, product selection, and commissioning. This makes the Danfoss Floor Heating
Dimensioning Programme a very valuable tool in
both the bidding and the implementation phases.