ST STTH60L06 User Manual

STTH60L06

Turbo 2 ultrafast high voltage rectifier

Features and benefits

■Ultrafast switching

■Low reverse current

■Low thermal resistance

■Reduces switching and conduction losses

Description

The STTH60L06, which is using ST Turbo 2 600 V technology, is specially suited for use in switching power supplies, and industrial applications, as rectification and discontinuous mode PFC boost diode. Thanks to its low VF characteristics, this device exhibits high performances in free-wheeling applications.

			A
		K
	DO-247
	STTH60L06W
Table 1.	Device summary
	Symbol		Value
	IF(AV)		60 A
	VRRM		600 V
	Tj (max)		175 °C
	VF (typ)		0.95 V
	trr (max)		70 ns

September 2011

Doc ID 10764 Rev 3

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www.st.com

Characteristics	STTH60L06

1 Characteristics

Table 2.	Absolute ratings (limiting values)
Symbol	Parameter			Value	Unit
VRRM	Repetitive peak reverse voltage			600	V
IF(RMS)	Forward rms current			90	A
IF(AV)	Average forward current δ = 0.5		Tc = 110 °C	60	A
IFSM	Surge non repetitive forward current		tp = 10 ms sinusoidal	600	A
Tstg	Storage temperature range			-65 to + 175	°C
Tj	Maximum operating junction temperature			175	°C

Table 3.

Thermal parameter

Symbol

Parameter

Value (max)

Unit

Rth(j-c)

Junction to case

0.75

°C/W

Table 4.

Static electrical characteristics

Symbol

Parameter

Test conditions

Min.

Typ.

Max.

Unit

I

(1)

Reverse leakage

Tj = 25 °C

V

R

= V

RRM

50

µA

current

R

Tj = 150 °C

160

1600

V

(2)

Forward voltage drop

Tj = 25 °C

I

= 60 A

1.55

V

F

Tj = 150 °C

F

0.95

1.2

1.Pulse test: tp = 5 ms, δ < 2 %

2.Pulse test: tp = 380 µs, δ < 2 %

To evaluate the maximum conduction losses use the following equation:

P = 0.93 x IF(AV) + 0.0045 IF2(RMS)

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STTH60L06									Characteristics
	Table 5.	Dynamic electrical characteristics
	Symbol	Parameter		Test conditions			Min.	Typ.	Max.	Unit
					IF = 0.5 A,
					Irr = 0.25 A				70
	trr	Reverse	Tj = 25 °C		IR =1 A					ns
		recovery time			IF = 1 A,
					dIF/dt = 50 A/µs			75	105
					VR = 30 V
	IRM	Reverse	Tj = 125 °C		IF = 60 A,
					VR = 400 V			14	19	A
		recovery current
					dIF/dt = 100 A/µs
	t	Forward recovery	T		IF = 60 A,
				= 25 °C	dI	/dt = 200 A/µs			500	ns
	fr	time	j		F
					VFR = 1.1 x VFmax
	VFP	Forward recovery	Tj = 25 °C		IF = 60 A,
					dIF/dt = 200 A/µs			3		V
		voltage
					VFR = 1.1 x VFmax

Doc ID 10764 Rev 3

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