ST STPS5H100B, STPS5H100B-TR, STPS5H100B-1 User Manual
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HIGH VOLTAGE POWER SCHOTTKY RECTIFIER
MAIN PRODUCT CHARACTERISTIC S
I
F(AV)
V
RRM
Tj (max) 175 °C
(max) 0.61 V
V
F
FEATURES AND BENEFITS
NEGLIGIBLE SWITCHING LOSSES
HIGH JUNCTION TEMPERATURE CAPABILITY
LOW LEAKAGE CURRE NT
GOOD TRADE OFF BETWEEN LEAKAGE
CURRENT AND FORWARD VOLTA GE DROP
AVALANCHE R ATE D
DESCRIPTION
Schottky barrier r ecti fier d esigned fo r hig h frequency miniat ure Switched Mode Power Sup plies such as adaptators and on board DC to
DC converters.
5 A
100 V
STPS5H100B/-1
K
A
NC
DPAK
STPS5H100B
K
A
K
NC
IPAK
STPS5H100B-1
ABSOLUTE RATINGS
(limiting values)
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
I
FSM
I
RRM
I
RSM
T
Repetitive peak reverse voltage 100 V
RMS forward current 10 A
Average forward current Tc = 165°C δ = 0.5 5 A
Surge non repetitive forward current tp = 10 ms sinusoidal 75 A
Repetitive peak reverse current tp = 2 µs square F = 1kHz 1 A
Non repetitive peak reverse current tp = 100 µs square 2 A
Storage temperature range - 65 to + 175°C
stg
Tj Maximum operating junction temperature * 175 °C
dV/dt Critical rate of rise of reverse voltage 10000 V/µs
dPtot
* :
July 1999 - Ed: 4B
dTj
<
1
Rth(j−a
thermal runaway condition for a diode on its own heatsink
)
1/5
STPS5H100B/-1
THERMAL RESISTANCES
Symbol Parameter Value Unit
R
th (j-c)
Junction to case 2.5
STATIC ELECTRICAL CHARACTE RISTICS
Symbol Parameter Tests Conditions Min. Typ. Max. Unit
°
C/W
* Reverse leakage current Tj = 25°CV
I
R
= V
R
Tj = 125°C1.34.5mA
** Forward voltage drop Tj = 25°CI
V
F
Tj = 125°CI
Tj = 25°CI
Tj = 125°CI
Pulse test : * tp = 5 ms, δ < 2%
** tp = 380 µs, δ < 2%
To evaluate the maximum conduction losses use the fol lowing equa tion :
P = 0.51 x I
Fig. 1:
+ 0.02 x I
F(AV)
F2(RMS)
Average forward power dissipation versus
average forward current.
PF(av)(W)
4.0
3.5
3.0
2.5
2.0
1.5
1.0
0.5
0.0
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0
δ = 0.05
δ = 0.1
IF(av) (A)
δ = 0.2
δ = 0.5
δ
=tp/T
δ = 1
T
tp
= 5 A 0.73 V
F
= 5 A 0.57 0.61
F
= 10 A 0.85
F
= 10 A 0.66 0.71
F
Fig. 2:
temperature (δ=0.5).
IF(av)(A)
6
5
4
3
2
1
=tp/T
δ
0
0 20 40 60 80 100 120 140 160 180
RRM
3.5
µ
A
Average forward current versus ambient
Rth(j-a)=Rth(j-c)
Rth(j-a)=80°C/W
T
tp
Tamb(°C)
2/5
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