SGS Thomson Microelectronics STPS80L15TV Datasheet
LOW DROP OR-ing POWER SCHOTTKYDIODE
MAINPRODUCT CHARACTERISTICS
STPS80L15TV
I
F(AV)
V
RRM
2 x 40 A
15 V
K2 A2
Tj (max) 125 °C
(max) 0.33V
V
F
FEATURESAND BENEFITS
VERYLOW DROP FORWARD VOLTAGEFOR
LESS POWER DISSIPATIONAND REDUCED
A1K1
K2
A2
HEATSINK
INSULATEDPACKAGE:
Insulatedvoltage= 2500V
Capacitance= 45 pF
(RMS)
K1
A1
DESCRIPTION
Dual Schottky rectifier suited for Switched Mode
PowerSuppliesand DC to DC power converters.
TM
Packaged in ISOTOP
, this device is especially
ISOTOP
TM
intended for use as an OR-ing diode in fault
tolerantpower supplyequipments.
ABSOLUTE RATINGS
(limitingvalues,per diode)
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
Repetitivepeakreverse voltage 15 V
RMSforward current 100 A
Averageforward current Tc = 110°C
40 A
δ =1
I
FSM
Surgenon repetitiveforwardcurrent tp = 10 ms
700 A
Sinusoidal
I
RRM
Repetitivepeakreverse current tp = 2 µs
2A
F = 1kHz
T
Storagetemperaturerange - 65 to+ 150 °C
stg
Tj Maximumoperatingjunctiontemperature 125 °C
dV/dt Criticalrate ofrise of reverse voltage 10000 V/µs
<
1
Rth(j−a
thermal runawayconditionfor a diodeon its own heatsink
)
dPtot
*:
dTj
ISOTOPis a trademarkof STMicroelectronics
July 1999- Ed:4A
1/4
STPS80L15TV
THERMALRESISTANCES
Symbol Parameter Value Unit
R
R
th (j-c)
th (c)
Junctionto case Perdiode 1 °C/W
Total 0.55
Coupling 0.1
STATICELECTRICAL CHARACTERISTICS
(perdiode)
Symbol Parameter Tests conditions Min. Typ. Max. Unit
I
* Reverseleakagecurrent Tj = 100°CV
R
Tj = 25°CV
= 5V 280 mA
R
= 12V 11
R
Tj = 100°C 0.44 1.1 A
V
* Forwardvoltagedrop Tj = 25°CI
F
Tj = 125°CI
Pulse test : * tp = 380µs,δ<2%
To evaluate theconduction losses use the followingequation :
P = 0.19 x I
+ 3.25 10-3xI
F(AV)
F2(RMS)
Fig. 1: Averageforward power dissipation versus
averageforwardcurrent(per diode).
PF(av)(W)
14
12
10
8
6
4
2
0
0 5 10 15 20 25 30 35 40 45
δ
δ = 0.2
=
δ
0.1
=
0.05
IF(av)(A)
δ
=
0.5
δ = 1
T
δ
=tp/T
tp
= 40A 0.43 V
F
= 40A 0.28 0.33
F
Fig. 2: Average forward current versus ambient
temperature(δ=1,per diode).
IF(av)(A)
45
40
35
30
25
20
15
10
5
0
0 25 50 75 100 125
δ
=tp/T
T
tp
Tamb(°C)
Rth(j-a)=Rth(j-c)
Rth(j-a)=5°C/W
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