SGS Thomson Microelectronics STPS5L60 Datasheet
®
MAIN PRODUCT CHARACTERISTICS
STPS5L60
POWER SCHOTTKY RECTIFIER
I
F(AV)
V
RRM
5A
60 V
Tj (max) 150°C
(max) 0.53 V
V
F
FEATURES AND BENEFITS
NEGLIGIBLE SWITCHING LOSSES
■
LOW FORWARD VOLTAGE DROP FOR
■
HIGHER EFFICIENCY
LOW THERMAL RESISTANCE
■
AVALANCHE CAPABILITY SPECIFIED
■
DESCRIPTION
Axial Power Schottky rectifier suited for Switch
Mode Power Supplies and high frequency
inverters.
PackagedinDO-201AD,thisdeviceis intended for
usein low voltage output forsmall battery chargers
& consumer SMPS such as DVD and
Set-Top-Box.
ABSOLUTE RATINGS (limiting values)
DO-201AD
STPS5L60
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
I
FSM
Repetitive peak reverse voltage
RMS forward current
Average forward current Tl = 100°C δ = 0.5
Surge non repetitive forward current Half wave, single phase
60 V
15 A
5A
150 A
tp=10ms
P
*:
ARM
T
Tj
dV/dt
dPtot
Repetitive peak avalanche power tp = 1µs Tj = 25°C
stg
Storage temperature range
Maximum operating junction temperature *
Critical rate of rise of reverse voltage (rated V
<
dTj Rth j a
July 2003 - Ed: 2A
, Tj = 25°C)
R
thermal runaway condition for a diode on its own heatsink
−1()
4000 W
- 65 to + 150 °C
150 °C
10000 V/µs
1/4
STPS5L60
THERMAL PARAMETERS
Symbol Parameter Value Unit
R
th(j-a)
R
th(j-l)
Junction to ambient
Junction to leads Lead length = 10 mm
STATIC ELECTRICAL CHARACTERISTICS
Symbol Parameter Tests conditions Min. Typ. Max. Unit
*
I
R
Reverse leakage current Tj = 25°C VR=V
RRM
Tj = 100°C
Tj = 125°C
V
*
F
Forward voltage drop Tj = 25°C IF=5A
Tj = 100°C
Tj = 125°C
Pulse test : * tp = 380 µs, δ <2%
To evaluate the maximum conduction losses use the following equation:
P=0.39xI
F(AV)
+ 0.028 x I
F2(RMS)
75 °C/W
15 °C/W
0.22 mA
10 25
40 100
0.47 0.52 V
0.43 0.49
0.42 0.48
Fig.1: Conduction lossesversus average current.
PF(av)(W)
3.5
3.0
2.5
2.0
1.5
1.0
0.5
0.0
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0
δ = 0.05
2/4
δ = 0.1
δ = 0.2
IF(av)(A)
δ = 0.5
δ
=tp/T
δ = 1
T
tp
Fig. 2: Average forward current versus ambient
temperature (δ = 0.5).
IF(av)(A)
6
5
4
3
2
δ
T
=tp/T
1
0
0 25 50 75 100 125 150
Rth(j-a)=Rth(j-l)
Rth(j-a)=75°C/W
tp
Tamb(°C)
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