®
LOW DROP POWER SCHOTTKY RECTIFIER
MAIN PRODUCT CHARACTERISTICS
STPS2L40U
I
F(AV)
V
RRM
2A
40 V
Tj (max) 150 °C
V
(max) 0.34V
F
FEATURES AND BENEFITS
VERY SMALL CONDUCTION LOSSES
n
NEGLIGIBLE SWITCHING LOSSES
n
LOW FORWARD VOLTAGE DROP
n
n
SURFACE MOUNT MINIATURE PACKAGE
AVALANCHE CAPABILITY SPECIFIED
n
DESCRIPTION
Single chip Schottky rectifiers suited to Switched
Mode Power Supplies and high frequency DC to
DC converters.
Packaged in SMB, this device is especially
intended for surface mounting and used in low
voltage, high frequency inverters, free wheeling
and polarity protection applications.
ABSOLUTE RATINGS (limiting values)
SMB
(JEDEC DO-214AA)
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
I
FSM
P
ARM
T
stg
Repetitive peak reverse voltage 40 V
RMS forward current 8 A
Average forward current TL= 130°C δ = 0.5 2 A
Surge non repetitive forward current tp = 10 ms Sinusoidal 75 A
Repetitive peak avalanche power tp = 1µs Tj = 25°C 2200 W
Storage temperature range - 65 to + 150 °C
Tj Maximum operating junction temperature * 150 °C
dV/dt Critical rate of rise of reverse voltage 10000 V/µs
dPtot
*:
<
dTj Rth j a
July 2003 - Ed: 2A
thermal runaway condition for a diode on its own heatsink
−1()
1/5
STPS2L40U
THERMAL RESISTANCES
Symbol Parameter Value Unit
R
th (j-l)
STATIC ELECTRICAL CHARACTERISTICS
Symbol Tests Conditions Tests Conditions Min. Typ. Max. Unit
I
R
V
Junction to lead SMB 20 °C/W
* Reverse leakage current Tj = 25°C VR=40V 220 µA
Tj = 100°C 20 mA
Tj = 125°C 38 80 mA
* Forward voltage drop Tj = 25°C IF= 1 A 0.39 V
F
Tj = 125°C 0.25 0.28
Tj = 25°C I
= 2 A 0.43
F
Tj = 125°C 0.31 0.34
Tj = 25°C I
= 4 A 0.5 V
F
Tj = 125°C 0.39 0.45
Pulse test:*tp=380µs, δ <2%
To evaluate the maximum conduction losses use the following equation :
P=0.22xI
Fig. 1: Average forward power dissipation versus
average forward current.
PF(av)(W)
1.0
0.8
0.6
0.4
0.2
0.0
0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 2.4 2.6
F(AV)
δ = 0.05
+ 0.06 I
δ = 0.1
F2(RMS)
δ = 0.2
IF(av) (A)
δ = 0.5
δ
=tp/T
δ = 1
T
Fig. 2: Average forward current versus ambient
temperature (δ=0.5).
IF(av)(A)
2.4
2.0
1.6
1.2
0.8
tp
0.4
0.0
0 25 50 75 100 125 150
δ
=tp/T
T
tp
Rth(j-a)=Rth(j-l)
Rth(j-a)=100°C/W
Tamb(°C)
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