SGS Thomson Microelectronics STPS1H100U, STPS1H100A Datasheet
®
HIGH VOLTAGE POWER SCHOTTKY RECTIFIER
MAIN PRODUCT CHARACTERISTIC S
STPS1H100A/U
I
F(AV)
V
RRM
1 A
100 V
Tj (max) 175 °C
(max) 0.62 V
V
F
FEATURES AND BENEFITS
NEGLIGIBLE SWITCHING LOSSES
HIGH JUNCTION TEMPERATURE CAPABILITY
LOW LEAKAGE CURRE NT
GOOD TRADE OFF BETWEEN LEAKAGE
CURRENT AND FORWARD VOLTA GE DROP
SMA
(JEDEC DO-214AC)
STPS1H100A
(JEDEC D O-214 AA )
SMB
STPS1H100U
AVALANCHE R ATE D
DESCRIPTION
Schottky rectifier designed for high frequency
miniature Switched Mode Power Supplies suc h as
adaptators and on board DC/DC converters.
Packaged in SMA or SMB.
ABSOLUTE RATINGS
(limiting values)
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
I
FSM
I
RRM
I
RSM
T
stg
Repetitive peak reverse voltage 100 V
RMS forward current 10 A
Average forward current TL = 160°C δ = 0.5 1 A
Surge non repetitive forward current tp = 10 ms sinusoidal 50 A
Repetitive peak reverse current tp = 2 µ square F = 1kHz 1 A
Non repetitive peak reverse current tp = 100 µs square 1 A
Storage temperature range - 65 to + 175
°
Tj Maximum operating junction temperature * 175 °C
dV/dt Critical rate of rise of reverse voltage 10000 V/µs
C
dPtot
* :
July 1999 - Ed: 3A
dTj
<
Rth(j−a
1
thermal runaway condition for a diode on its own heatsink
)
1/6
STPS1H100A/U
THERMAL RE SISTA NC ES
Symbol Parameter Value Unit
R
th (j -l)
Junction to lead SMA 30
°
SMB 25
STATIC ELECTRICAL CHARACTE RISTICS
Symbol Parameter Tests Conditions Min. Typ. Max. Unit
* Reverse leakage current Tj = 25°CV
I
R
= V
R
RRM
1
Tj = 125°C 0.2 0.5 mA
** Forward voltage drop Tj = 25°CI
V
F
Tj = 125°C I
Tj = 25°CI
Tj = 125°C I
Pulse test : * tp = 5 ms, δ < 2%
** tp = 380 µs, δ < 2%
= 1 A 0.77 V
F
= 1 A 0.58 0.62
F
= 2 A 0.86
F
= 2 A 0.65 0.7
F
To evaluate the maximum conduction losses use the following equation :
P = 0.54 I
F(AV)
+ 0.08 I
F2(RMS )
C/W
µ
A
Fig. 1:
Average forward power dissipation versus
average forward current.
PF(av)(W)
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0.0
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2
2/6
δ = 0.05
δ = 0.1
IF(av) (A)
δ = 0.2
δ = 0.5
δ
δ = 1
T
=tp/T
Fig. 2:
Average forward current versus ambient
temperature (δ=0.5).
IF(av)(A)
1.2
1.0
0.8
0.6
0.4
tp
0.2
=tp/T
δ
0.0
0 20 40 60 80 100 120 140 160 180
Rth(j-a)=120°C/W
Rth(j-a)=100°C/W
T
tp
Tamb(°C)
Rth(j-a)=Rth(j-l)
Loading...