SGS Thomson Microelectronics STPS15L25G, STPS15L25D Datasheet
®
LOW DROP POWER SCHOTTK Y RECTIFIER
MAIN PRODUCT CHARACTERISTIC S
STPS15L25D/G
I
F(AV)
V
RRM
15 A
25 V
Tj (max) 150 °C
V
(max) 0.35 V
F
FEATURES
VERY LOW FORWARD VOLTAGE DROP
FOR LESS POWER DISSIPATION AND REDUCED HEATSINK
OPTIMIZED CONDUCTION/REVERSE LOSSES
TRADE-OFF WHICH MEANS THE HIGHEST
EFFICIENCY IN THE APPLICATIONS
DESCR IPTION
Single Schottky rectifier suited for Switched Mode
Power Supplies and high frequency DC to DC converters (V RM
Packaged in TO-220AC or D
).
S
2
PAK, this device is
especially intended for use as a Rectifier at the
secondary of 3.3V SMP S and DC/ DC units.
TO-220AC
STPS15L25D
K
A
A
K
NC
D2PAK
STPS15L25G
ABSOLUTE RATINGS
(limiting values)
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
I
FSM
I
RRM
I
RSM
T
stg
Repetitive peak reverse voltage 25 V
RMS forward current 30 A
Average forward current Tc = 145°C δ = 0.5 15 A
Surge non repetitive forward current tp = 10ms Sinusoidal 250 A
Repetitive peak reverse current tp=2µs square F=1kHz 1 A
Non repetitive peak reverse current tp = 100µs square 4 A
Storage temperature range - 65 to + 150°C
Tj Max imum oper ating junction temperature * 150
dV/dt Critical rate of rise of reverse voltage 10000 V /µs
dPtot
* :
June 1999 - Ed : 4B
dTj
<
1
Rth(j−a
thermal runaway condition for a diode on its own heatsink
)
°
C
1/5
STPS15L25D/G
THERMAL RE SISTA NC ES
Symbol Parameter Value Unit
R
th(j-c)
Junction to case
1
°
STATIC ELECTRICAL CHARACTERISTICS
Symbol Parameters Test conditions M in. Typ. Max. Unit
* Reverse leakage current Tj = 25° C VR = V
I
R
Tj = 125°C
* Forward voltage drop Tj = 25°C IF = 15A 0.46 V
V
F
Tj = 125°C I
Tj = 25°C I
Tj = 125°C I
Pulse test : * tp = 380 µs, δ < 2%
RRM
225 450 mA
= 15A 0.3 0.35
F
= 30A
F
= 30A 0.41 0.46
F
1.3 mA
0.56
To evaluate the maximum conduction losses use the following equation :
P = 0.24 x I
F(AV)
+ 0.0073 I
F2(RMS)
C/W
Fig.1 :
Average forward power dissipation versus
average forward current.
PF(av)(W)
8
7
6
5
4
3
2
1
0
0 2 4 6 8 10 12 14 16
2/5
δ = 0.05
δ = 0.1
IF(av) (A)
δ = 0.2
δ = 0.5
=tp/T
δ
δ = 1
T
Fig.2 :
Average forward current versus ambient
temperature ( δ = 0.5).
IF(av)(A)
16
14
12
10
8
6
δ
=tp/T
T
tp
4
tp
2
0
0 25 50 75 100 125 150
Rth(j-a)=Rth(j-c)
Rth(j-a)=50°C/W
Tamb(°C)
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