SGS Thomson Microelectronics SMBYW04-200 Datasheet
SMBYW04-200
®
HIGH EFFICIENC Y FA ST RECO VE RY DIO D E
MAIN PRODUCT CHARACTERISTI CS
I
F(AV)
V
RRM
(max) 0.85 V
V
F
Tj (max) 150 ° C
FEATURES AND BENE FITS
SUITED T O SMPS AND DRIVES
SURFACE MOUNT PACKAGE
VERY LOW F ORW A RD LO SSE S
NEGLIGIBLE SWITCHING LOSSE S
HIGH SURGE CURRENT CAPAB ILITY
DESCRIPTION
Single chip rectifier suited to Switch Mode Power
Supplies and high frequency converters.
Packaged in DPAK and SMC, this surface mount
device is intended for use in low voltage, high
frequency inverters, free wheeling and rectification
applications.
4 A
200 V
3
4
DPAK
BYW4200B
2
4(TAB)
2
1(nc)
BYW4200B
3
SMC
(JEDEC DO-214AB)
SMBYW04-200
ABSOLUTE RATINGS
(limiting values)
Symbol Parameter Value Unit
V
RRM
I
F(RMS)
I
F(AV)
I
FSM
Repetitive peak reverse voltage 200 V
RMS forward current 10 A
Average forward current
δ
= 0.5
Surge non repetitive forward current tp = 10 ms
DPAK
SMC
Tcase = 130° C
Tlead = 70°C
4A
70 A
sinusoidal
Tstg Storage temperature range - 65 to + 150
Tj Maximum operating junction temperature 150 °C
October 1999 - Ed: 4C
°
C
1/6
SMBYW04-200 / BYW4200B
THERMAL RESISTANCE
Symbol Parameter Package Value Unit
R
R
th (j-c)
th (j-l)
Junction to case DPAK 5
Junction to leads SMC 20
STATIC ELECTRICAL CHARACTER ISTICS
Symbol Tests Conditions Tests Conditions Min. Typ. Max. Unit
I
* Reverse leakage current Tj = 25°CV
R
= V
R
RRM
10
Tj = 100°C 0.15 0.5 mA
V
** Forward voltage drop Tj = 25°CI
F
Tj = 100°CI
Pulse test : * tp = 5 ms, δ < 2 %
** tp = 380 µs, δ < 2%
To evaluate the maximum conduction losses use the fol lowing equ ation :
P = 0.7 x I
F(AV)
+ 0.037 I
F2(RMS)
= 12 A 1.25 V
F
= 4 A 0.8 0.85
F
°
C/W
°
C/W
µ
A
RECOVERY CHARACTE RISTICS
Symbol Test Conditions Min. Typ. Max. Unit
t
rr
t
fr
V
FP
Fig. 1:
Tj = 25°C IF = 1A
V
= 30V
F
Tj = 25°C IF = 4A
V
= 1.1 x VF max
FR
Tj = 25°C IF = 4A dIF/dt = -50 A/µs5 V
Average forward power dissipation versus
/dt = -50 A/µs2635ns
dI
F
/dt = -50 A/µs20 ns
dI
F
Fig. 2:
Peak current ve r su s f o rm f a ct or.
average forward current.
PF(av)(W)
4.5
4.0
3.5
3.0
2.5
2.0
1.5
1.0
0.5
0.0
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
δ = 0.05
δ = 0.1
IF(av) (A)
δ = 0.2
δ = 0.5
=tp/T
δ
T
δ = 1
tp
IM(A)
20
18
16
14
12
10
8
P=1.0W
6
4
2
0
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
P=1.5W
P=2.0W
P=2.5W
δ
δ
T
=tp/T
tp
2/6
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