SGS Thomson Microelectronics MDV04-600 Datasheet
®
HIGH VOLTAGE ULTRA-FAST DIODE FOR VIDEO
MAJOR PRODUCT CHARACTE RISTICS
MDV04-600
I
Fpeak
V
RRM
t
rr
(max) 1.2 V
V
F
4 A
600 V
55 ns
FEATURES AND BENE FITS
TURBOSWITCH TM OUTSTANDING BENEFITS.
HIGH REVERSE VO LTAGE : 600 V
LOW POWER LOSSES INDUCING LOW
TEMPERATURE A ND HIGH RELIABILITY.
OPTIMIZED TRADE-OFF BETWEEN trr AND
SOFTNESS FOR VIDEO HORIZONTAL
DEFLECTION.
DESCRIPTION
High voltage ultra-fast diode especially designed
for modulation and flyback rectification in standard
and high resolution displays for TV’s and monitors.
The device is packaged in a DO-201AD axial
enveloppe.
DO-201AD
(plastic)
ABSOLUTE RATINGS
(limiting values)
Symbol Parameter VALUE Unit
V
RRM
peak Forward peak current (1)
I
F
Repetitive peak reverse voltage 600 V
δ
=0.5 Ta=115°C
4A
triangular
I
FRM
I
FSM
Repetitive peak forward
current
Surge non repetitive forward
tp=5µs
100 A
F=1kHz square
tp = 10 ms sinusoidal 80 A
current
T
stg
T
j
Storage temperature range
- 40 to 150 °C
Maximum operating junction temperature 150 °C
(1) on infinite heatsink with 10mm lead length
August 1999 - Ed: 4A
1/4
MDV04-600
THERMAL RE SISTA NC ES
Symbol Parameter Max. Unit
R
th(j-l)
R
th(j-a)
Junction to lead 20
Junction to ambient on printed circuit L lead = 10mm 75
STATIC ELECTRICAL CHARACTER ISTICS
Symbol Parameter Test Conditions Typ. Max. Unit
*
I
R
V
** Forward voltage drop IF = 4 A Tj = 25°C
F
Reverse leakage current V
= 480V Tj = 25°C
R
Tj = 125°C
Tj = 125°C
50
0.75
1.28
1.20
Pulse test : * tp = 5 ms, δ < 2%
**tp = 380 µs, δ < 2%
DYNAMIC ELECTRICAL CHARACTE RISTICS
TURN-OFF SWITCHING
Symbol Parameter Test Conditions Typ. Max. Unit
t
rr
Reverse rec overy tim e IF = 0.5A IR = 1A
55 75 ns
Irr = 0.25A
= 100 mA IR = 100 mA
I
F
130 ns
Irr = 10mA
°
C/W
°
C/W
µ
mA
A
V
V
DYNAMIC ELECTRICAL CHARACTERIS TICS
TURN-ON SWITCHING
Symbol Parameter Test Conditions Typ. Max. Unit
t
fr
V
FP
Forward rec overy time IF = 4 A dIF/dt = 100 A/µs
Peak forward voltage 15 V
Measured at1.1 x V
Tj = 25°C
max.
F
0.5
To evaluate the maximum conduction losses use the following equation :
x I
1.0
P
=
δ
: duty cycle
: Peak current
I
p
Ex : for I
2/4
p
2
= 4 A and δ = 0.5, P = 1.2 Watts.
p
x
δ +
0.050
2
x I
p
x δ
3
µ
s
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