MAX6920
12-Output, 76V, Serial-Interfaced
VFD Tube Driver
8 _______________________________________________________________________________________
Since dissipation is proportional to current squared, the
maximum current that can be delivered for a given multiplex ratio is given by:
I
PEAK
= (grids x 1600)
1/2
mA
where grids is the number of grids in a multiplexed display.
This means that a duplex application (two grids) can use
a repetitive peak current of 56.5mA, a triplex application
(three grids) can use a repetitive peak current of 69.2mA,
and higher multiplex ratios are limited to 75mA.
Paralleling Outputs
Any number of outputs within the same package may
be paralleled in order to raise the current drive or
reduce the output resistance. Only parallel outputs
directly (by shorting outputs together) if the interface
control can be guaranteed to set the outputs to the
same level. Although the sink output is relatively weak
(typically 750Ω), that resistance is low enough to dissipate 530mW when shorted to an opposite level output
at a VBBvoltage of only 20V. A safe way to parallel outputs is to use diodes to prevent the outputs from sinking current (Figure 4). Because the outputs cannot sink
current from the VFD tube, an external discharge resistor, R, is required. For static tubes, R can be a large
value such as 100kΩ. For multiplexed tubes, the value
of the resistor can be determined by the load capacitance and timing characteristics required. Resistor Rl
discharges tube capacitance C to 10% of the initial
voltage in 2.3 x RC seconds. So, for example, a 15kΩ
value for R discharges 100pF tube grid or anode from
40V to 4V in 3.5µs, but draws an additional 2.7mA from
the driver when either output is high.
Power Dissipation
Take care to ensure that the maximum package dissipation ratings for the chosen package are not exceeded. Over dissipation is unlikely to be an issue when
driving static tubes, but the peak currents are usually
higher for multiplexed tubes. When using multiple driver devices, try to share the average dissipation evenly
between the drivers.
Determine the power dissipation (PD) for the MAX6920
for static tube drivers with the following equation:
PD= (VCCx ICC) + (VBBx IBB) + ((VBB- VH) x
I
ANODE
x A))
where:
A = number of anodes driven (a MAX6920 can drive a
maximum of 12).
I
ANODE
= maximum anode current.
(V
BB
- VH) is the output voltage drop at the given maxi-
mum anode current I
OUT
.
A static tube dissipation example follows:
VCC= 5V ±5%, VBB= 10V to 18V, A = 12, I
OUT
= 2mA
PD= (5.25V x 0.7mA) + (18V x 0.9mA) + ((2.5V x
2mA/25mA) x 2mA x 12) = 24.7mW
Determine the power dissipation (PD) for the MAX6920
for multiplex tube drivers with the following equation:
PD= (VCCx ICC) + (VBBx IBB) + ((VBB- VH) x I
ANODE
x A) + ((VBB- VH) x I
GRID
))
where:
A = number of anodes driven
G = number of grids driven
I
ANODE
= maximum anode current
I
GRID
= maximum grid current
The calculation presumes all anodes are on but only
one grid is on. The calculated PDis the worst case,
presuming one digit is always being driven with all its
anodes lit. Actual PDcan be estimated by multiplying
this PDfigure by the actual tube drive duty cycle, taking
into account interdigit blanking and any PWM intensity
control.
A multiplexed tube dissipation example follows:
VCC= 5V ±5%, VBB= 36V to 42V, A = 6, G = 6,
I
ANODE
= 0.4mA, I
GRID
= 24mA
PD= (5.25V X 0.7mA)+ (42V x 0.9mA) + ((2.5V x
0.4mA/25mA) x 0.4mA x 6) +
((2.5V x 24mA/25mA) x 24mA) = 99mW
Thus, for a 20-pin wide SO package (T
JA
= 1 / 0.01 =
+100°C/W from Absolute Maximum Ratings), the maximum allowed ambient temperature TAis given by:
T
J(MAX)
= TA+ (PDx TJA) = +150°C = TA+ (0.099 x
+100°C/W)
So TA= +140°C.