Set the error-amplifier compensation zero formed by R
C
and CCequal to the load-impedance pole frequency,
f
PLOAD
, at maximum load. Calculate CCas:
C
C
= (C
OUT
✕ R
OUT
)/R
C
500kHz Switching
The following design example is for the application circuit shown in Figures 1 and 2:
V
OUT
= 1.8V
I
OUT(MAX)
= 6A
C
OUT
= 180µF
R
ESR
= 0.04Ω
gmEA= 50µs
gmc = 18.2s
f
SWITCH
= 500kHz
R
OUT
= V
OUT/IOUT(MAX)
= 1.8V/6 A = 0.3Ω
fpDC= 1/(2π ✕ C
OUT
✕ (R
OUT
+ R
ESR
) = 1/(2 π ✕ 180 ✕
10
-6
✕
(0.3 + 0.04) = 2.6kHz.
fz
ESR
= 1/(2π ✕ C
OUTRESR
) = 1/(2 π ✕ 180 ✕10
-6
✕
0.04) = 22.1kHz.
Pick the closed-loop unity-gain crossover frequency (fc)
at 60kHz. Determine the switching regulator DC gain:
GDC= gmc ✕ R
OUT
= 18.2 ✕ 0.3 = 5.46
then:
RC= (V
OUT
✕ f
C
)/(gm
EA
✕ VFB✕ GDC✕ fp
LOAD
) =
(1.8 ✕ 60kHz)/(50 ✕ 10
-6
✕
0.8 ✕ 5.46 ✕ 2.6kHz) ≈ 190kΩ
(1%), choose RC= 180kΩ, 1%
CC= (C
OUT
✕ (R
OUT
+ R
ESR
))/RC= (180uF ✕ (0.3 +
0.04))/180kΩ≈340pF, choose CC= 330pF, 10%
Table 2 shows the recommended values for RCand C
C
for different output voltages.
1MHz Switching
Following procedure outlines the compensation
process of the MAX1945 for 1MHz operation with all
ceramic output capacitors (Figure 3). The basic regulator loop consists of a power modulator, an output-feedback divider, and an error amplifier. The switching
regulator has a DC gain set by gmc ✕ R
OUT
, where
gmc is the transconductance from the output voltage of
the error amplifier to the output inductor current. The
load impedance of the switching modulator consists of
a pole-zero pair set by R
OUT
, the output capacitor
(C
OUT
), and its ESR. The following equations define the
power train of the switching regulator:
Regulator DC Gain:
GDC= ∆V
OUT
/∆V
COMP
= gmc ✕ R
OUT
Load-Impedance Pole Frequency:
fp
LOAD
= 1/(2 ✕ π ✕ C
OUT
✕ (R
OUT+RESR
))
Load-Impedance Zero Frequency:
fz
ESR
= 1/(2 ✕ π ✕ C
OUT
✕ R
ESR
)
where, R
OUT
= V
OUT/IOUT(MAX)
, and gmc = 18.2. The
feedback divider has a gain of G
FB
= VFB/V
OUT
, where
V
FB
is equal to 0.8V. The transconductance error ampli-
fier has a DC gain, G
EA(DC)
, of 70dB. The compensation capacitor, CC, and the output resistance of the
error amplifier, R
OEA
(20MΩ), set the dominant pole.
C
C
and RCset a compensation zero. Calculate the
dominant pole frequency as:
fpEA= 1/(2π ✕ C
C
✕ R
OEA
)
Determine the compensation zero frequency as:
fzEA= 1/(2π ✕ C
C
✕ R
C
)
For best stability and response performance, set the
closed-loop unity-gain frequency much higher than the
load impedance pole frequency. In addition, set the
closed-loop unity-gain crossover frequency less than
one-fifth of the switching frequency. However, the maxi-
MAX1945R/MAX1945S
1MHz, 1% Accurate, 6A Internal Switch
Step-Down Regulators
______________________________________________________________________________________ 15