Friedrich Room Model Number Code .........................................................................................................4
Application and Sizing ..............................................................................................................................5
Instructions For Using Cooling Load Estimate Form .................................................................................6
Cooling Load Estimate Form .....................................................................................................................7
Heat Load Form ........................................................................................................................................8
Heating Load Form Friedrich Unit Heat Pumps ..........................................................................................9
Fan Motor ................................................................................................................................................ 17
Capacitor, Run .........................................................................................................................................18
System Control Switch (Heat Pump & Electric Heat Models) ................................................................... 18
Heat Element ...........................................................................................................................................21
Drain Pan Valve........................................................................................................................................ 22
"YS" - "YM" - "YL" Series Parts List ........................................................................................................ 39
"ES" - "EM" Series Parts List .................................................................................................................. 46
"EL" Series Parts List .............................................................................................................................. 51
"EK" Series Parts List ............................................................................................................................. 56
Page 3
FRIEDRICH ROOM MODEL NUMBER CODE
1st DIGIT - FUNCTION
S = Straight Cool, Value Series
C = Straight Cool, Budget Series
Y = Heat Pump
E = Electric Strip
K = Straight Cool, Challenger Series
W = Thru-The-Wall, WallMaster Series
2nd DIGIT - TYPE
C = Casement
P = PowerMiser “Portable”
Q = QStar
S = Small Chassis
M = Medium Chassis
L = Large Chassis
W = Built-In
H = Hazardgard
3rd & 4th DIGITS - APPROXIMATE BTU/HR (Cooling)
Heating BTU/HR capacity listed in Specifications/Performance Data Section
In the application and sizing of room air conditioners for cooling, it is most important to give full consideration to all
factors which may contribute to the heat loss or gain of the space to be conditioned. It is therefore necessary to make
a survey of the space to be conditioned and calculate the load requirements before a selection of the size of the
equipment needed can be made.
The load requirement may be determined very easily by simply using the standard "AHAM" Load Calculating Form, on
Page 7. This form is very easy to use and is self explanatory throughout. It is necessary only to insert the proper
measurements on the lines provided and multiply by the given factors, then add the result for the total load requirements.
Cooling load requirements are generally based on the cooling load for comfortable air conditioning which does not
require specific conditions of inside temperature and humidity. The load calculation form is based on outside design
temperature of 95° FDB and 75° FWB. It can be used for areas in the Continental United States having other outside
design temperatures by applying a correction factor for the particular locality as determined from the map shown on
Page 7.
When sizing a TwinTemp unit for cooling and heating, we must remember that the heating capacity of any given unit
varies directly with the outdoor ambient temperature. Also, we must keep in mind the average low temperatures which
might be experienced in the locality where the unit is to be installed. Therefore, when sizing a TwinTemp unit, both
cooling and heating requirements must be calculated. Do not oversize, or undersize, one phase of the unit’s capacity
at the expense of the other. In those cases where the unit will provide satisfactory cooling at all times but will be
inadequate for those few times that the outdoor temperature is below the maximum low for the unit, additional auxiliary
heating facilities must be provided to insure that adequate heat is available at all times.
Page 5
INSTRUCTIONS FOR USING COOLING LOAD ESTIMATE
FORM FOR ROOM AIR CONDITIONERS
(AHAM PUB. NO. RAC-1)
A.This cooling load estimate form is suitable for estimating the cooling load for comfort air conditioning installations
which do not require specific conditions of inside temperature and humidity.
B.The form is based on an outside design temperature of 95°F dry bulb and 75°F wet bulb. It can be used for areas
in the continental United States having other outside design temperatures by applying a correction factor for the
particular locality as determined from the map.
C.The form includes "day" factors for calculating cooling loads in rooms where daytime comfort is desired (such as
living rooms, offices, etc.)
D.The numbers of the following paragraphs refer to the corresponding numbered item on the form:
1.Multiply the square feet of window area for each exposure by the applicable factor. The window area is the
area of the wall opening in which the window is installed. For windows shaded by inside shades or venetian
blinds, use the factor for "Inside Shades." For windows shaded by outside awnings or by both outside
awnings and inside shades (or venetian blinds), use the factor for "Outside Awnings." "Single Glass" includes
all types of single thickness windows, and "Double Glass" includes sealed airspace types, storm windows,
and glass block. Only one number should be entered in the right hand column for Item 1, and this number
should represent only the exposure with the largest load.
2.Multiply the total square feet of all windows in the room by the applicable factor.
3a.Multiply the total length (linear feet) of all walls exposed to the outside by the applicable factor. Doors should
be considered as being part of the wall. Outside walls facing due north should be calculated separately from
outside walls facing other directions. Walls which are permanently shaded by adjacent structures should be
considered "North Exposure." Do not consider trees and shrubbery as providing permanent shading. An uninsulated frame wall or a masonry wall 8 inches or less in thickness is considered "Light Construction." An
insulated wall or masonry wall over 8 inches in thickness is considered "Heavy Construction."
3b.Multiply the total length (linear feet) of all inside walls between the space to be conditioned and any
unconditioned spaces by the given factor. Do not include inside walls which separate other air conditioned
rooms.
4.Multiply the total square feet of roof or ceiling area by the factor given for the type of construction most
nearly describing the particular application (use one line only.)
5.Multiply the total square feet of floor area by the factor given. Disregard this item if the floor is directly on the
ground or over a basement.
6.Multiply the number of people who normally occupy the space to be air conditioned by the factor given. Use
a minimum of 2 people.
7.Determine the total number of watts for light and electrical equipment, except the air conditioner itself, that
will be in use when the room air conditioning is operating. Multiply the total wattage by the factor given.
8.Multiply the total width (linear feet) of any doors or arches which are continually open to an unconditioned
space by the applicable factor.
NOTE: Where the width of the doors or arches is more than 5 feet, the actual load may exceed the
calculated value. In such cases, both adjoining rooms should be considered as a single large room, and the
room air conditioner unit or units should be selected according to a calculation made on this new basis.
9.Total the loads estimated for the foregoing 8 items.
10.Multiply the subtotal obtained in item 9 by the proper correction factor, selected from the map, for the
particular locality. The result is the total estimated design cooling load in BTU per hour.
E.For best results, a room air conditioner unit or units having a cooling capacity rating (determined in accordance
with the NEMA Standards Publication for Room Air Conditioners, CN 1-1960) as close as possible to the estimated
load should be selected. In general, a greatly oversized unit which would operate intermittently will be much less
satisfactory than one which is slightly undersized and which would operate more nearly continuously.
F.Intermittent loads such as kitchen and laundry equipment are not included in this form.
Page 6
COOLING LOAD ESTIMATE FORM
HEAT GAIN FROM
1.WINDOWS: Heat gain from the sun.
Northeast
East
Southeast
South
Southwest
West
Northwest
North
2.WINDOWS: Heat by conduction
(Total of all windows.)
Single glass
Double glass or glass block
3.WALLS: (Based on linear feet of wall)
a. Outside walls
North Exposure
Other than North exposure
b. Inside Walls (between conditioned and
unconditioned spaces only.)
4.ROOF OR CEILING: (Use one only)
a. Roof, Un-insulated
b. Roof, 1 inch or more insulation
c. Ceiling, occupied space above
d. Ceiling, insulated, with attic space above
e. Ceiling, Un-insulated, with attic space above
* These factors are for single glass
only. For glass block, multiply the
above factors by 0.5; for double
glass or storm windows, multiply
the above factors by 0.8.
QUANTITY
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____ ft.
____ ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
____sq. ft.
5.Floor: (Disregard if floor is directly on ground or over
a basement.
6.NUMBER OF PEOPLE
7.LIGHTS AND ELECTRICAL EQUIPMENT IN USE
8.DOORS AND ARCHES CONTINUOUSLY OPENED TO
UNCONDITIONED SPACE: (TOTAL LINEAR FEET OF
WIDTH.)
9.SUBTOTAL
10. TOTAL COOLING LOAD (BTU per hour to be used for
selection of room air conditioner(s).)
____ Total in Item 9 X ____(Factor from Map) =_______
____sq. ft.
____
____watts
____ft.
*****
3
600
3
300
*****
_____
_____
_____
_____
_____
Page 7
HEAT LOAD FORM
The heat load form, Page 9, may be used by servicing
personnel to determine the heat loss of a conditioned
space and the ambient winter design temperatures in
which the unit will heat the calculated space.
The upper half of the form is for computing the heat loss
of the space to be conditioned. It is necessary only to
insert the proper measurements on the lines provided
and multiply by the given factors, then add this result for
the total heat loss in BTU/Hr./°F.
The BTU/Hr. per °F temperature difference is the 70°F
inside winter designed temperature minus the lowest
outdoor ambient winter temperature of the area where
the unit is installed. This temperature difference is used
as the multiplier when calculating the heat loss.
The graph shows the following:
Left Hand ScaleUnit capacity BTU/Hr. or heat loss
BTU/Hr.
Bottom ScaleOutdoor ambient temperature,
base point.
Heat Pump ModelBTU/Hr. capacity heat pump will
deliver at outdoor temperatures.
Balance PointMaximum BTU/Hr. heat pump will
deliver at indicated ambient temperature.
Below is an example using the heat load form:
A space to be conditioned is part of a house geographically located in an area where the lowest outdoor ambient winter temperature is 40°F. The calculated heat loss
is 184 BTU/Hr./°F.
Subtract 40°F (lowest outdoor ambient temperature for
the geographical location) from 70°F (inside design temperature of the unit) for a difference of 30°F. Multiply 184
by 30 for a 5500 BTU/Hr. total heat loss for the calculated space.
On the graph, plot the base point (70°) and a point on the
40°F line where it intersects with the 5500 BTU/Hr. line
on the left scale. Draw a straight line from the base
point 70 through the point plotted at 40°F. This is the
total heat loss line.
Knowing that we have a 5500 BTU/Hr. heat loss, and we
expect that our heat pump will maintain a 70°F inside
temperature at 40°F outdoor ambient, we plot the selected unit capacity BTU/Hr. of the unit between 35° and
60° on the graph and draw a straight line between these
points. Where the total heat loss line and the unit capacity line intersect, read down to the outdoor ambient temperature scale and find that this unit will deliver the required BTU/Hr. capacity to approximately 30°F.
Page 8
HEATING LOAD FORM
FRIEDRICH ROOM UNIT HEAT PUMPS
BTU/HR PER
WALLS: (Linear Feet°F. TEMP. DIFFERENCE
2" InsulationLin. Ft. x 1.6
AverageLin. Ft. x 2.6
WINDOWS & DOORS (Area, sq. ft.
Single Glass:Sq. Ft. x 1.13
Double Glass:Sq. Ft. x 0.61
INFILTRATION - WINDOWS & DOORS: AVG.Lin. Ft. x 1.0
LooseL i n. Ft . x 2 . 0
CEILING: (Area, Sq. Ft.)
Insulated (6")Sq. Ft. x 0.07
Insulated (2")Sq. Ft. x 0.10
Built-up Roof (2" insulatedSq. Ft. x 0.10
Built-up Roof (1/2" insulated)Sq. Ft. x 0.20
No InsulationSq. Ft. x 0.33
FLOOR: (Area, Sq. Ft.)
Above Vented Crawl space
Insulated (1:)Sq. Ft. x 0.20
Un-insulatedSq. Ft. x 0.50
* Slab on GroundLin. Ft. x 1.70
1" Perimeter insulationLin. Ft. x 1.00
* Based on Linear Feet of outside wallTOTAL HEAT LOSS PER °F BTU/HR/°F
Multiply total BTU/HR/°F X 30 and plot on the graph below at 40°F. Draw a straight line from the
70 base point thru the point plotted at 40°F. The intersection of this heat loss line with the unit
capacity line represents the winter design heating load.
In the cooling cycle, both capillary tubes feed the evaporator coil
Heating Cycle (Refer to Chart Below)
In the heating cycle, the one-way check is closed and the refrigerant flows through one capillary only to the
condenser
Page 14
INSTALLATION INSTRUCTIONS
FOR DC-2 DRAIN KIT
STEP 1Before sliding chassis into outer shell, turn chassis on its side and add drain hole by drilling ½"
diameter hole as shown in Figure 1.
STEP 2DC-2 mounts to the bottom of the outer shell as shown in Figure 2 on the right side as you face
the unit. Use two (2) 10 - 24 x 3/8" long machine screws and 10 - 24 hex nuts provided.
STEP 3SQ, KQ, YQ Models - Drill two ¼" holes in outer shell as shown in Figure 3. Also drill a 3/8"
diameter hole in the base pan 3½" from the back and 3½" from right side.
STEP 4Small and Medium Chassis Models - Mount in second and third holes from the rear of shell; See
Figure 4.
STEP 5Large Chassis Models - Mount in third and fourth holes from the rear of shell; see Figure 5.
STEP 6Connect a suitable length of garden hose or other tubing to end of the drain tube to drain the
condensate away.
FIGURE 1FIGURE 2
RIGHT SIDE
APPROXIMATE
LOCATION OF
EMBOSSMENT.
DRILL 1/2" DIA.
HOLE
BACK OF BASE PAN
FIGURE 3
FIGURE 4FIGURE 5
2ND & 3RD HOLES
FROM REAR OF
SHELL
10-24X 3/8" LONG
SCREWS
DRAIN PLATE
10X24 NUTS
3RD & 4TH HOLES
FROM REAR OF
SHELL
SQ, KQ, YQ MODELS
BOTTOM VIEW
SMALL & MEDIUM
CHASSIS MODELS
BOTTOM VIEW
LARGE
CHASSIS MODELS
BOTTOM VIEW
Page 15
COMPONENT OPERATION & TESTING
WARNING
DISCONNECT ELECTRICAL POWER TO
UNIT BEFORE SERVICING OR TESTING
COMPRESSORS
GROUND TEST
Use an ohmmeter set on its highest scale. Touch one
lead to the compressor body (clean point of contact as
a good connection is a must) and the other probe in turn
to each compressor terminal (see Figure 2.) If a reading
is obtained, the compressor is grounded and must be
replaced.
Compressors are single phase, 115 or 230/208 volt,
depending on the model unit. All compressor motors are
permanent split capacitor type using only a running
capacitor across the start and run terminal.
All compressors are internally spring mounted and
externally mounted on rubber isolators.
COMPRESSOR WINDING TEST (See Figure 1)
Remove compressor terminal box cover and disconnect
wires from terminals. Using an ohmmeter, check
continuity across the following:
1. Terminal "C" and "S" - no continuity - open winding
- replace compressor.
2. Terminal "C" and "R" - no continuity - open winding
- replace compressor.
3. Terminal "R" and "S" - no continuity - open winding - replace compressor.
Figure 2: Typical Ground Test
CHECKING COMPRESSOR EFFICIENCY
The reason for compressor inefficiency is normally due
to broken or damaged suction and/or discharge valves,
reducing the ability of the compressor to pump refrigerant
gas.
This condition can be checked as follows:
1. Install a piercing valve on the suction and
discharge or liquid process tube.
2. Attach gauges to the high and low sides of the
system.
Figure 1:Compressor Winding Test
Page 16
3. Start the system and run a “cooling or heating
performance test.”
If test shows:
A. Below normal high side pressure.
B. Above normal low side pressure.
C. Low temperature difference across coil.
The compressor valves are faulty - replace the
compressor.
THERMAL OVERLOAD (External)
Some compressors are equipped with an external
overload which is located in the compressor terminal
box adjacent to the compressor body (see Figure 3.)
The overload is wired in series with the common motor
terminal. The overload senses both major amperage and
compressor temperature. High motor temperature or
amperage heats the disc causing it to open and break
the circuit to the common motor terminal.
Figure 3: External Overload
Should the internal temperature and/or current draw become excessive, the contacts in the overload will open,
turning off the compressor. The overload will automatically reset, but may require several hours before the heat
is dissipated.
CHECKING THE INTERNAL OVERLOAD
(see Figure 4.)
Figure 4INTERNAL OVERLOAD
Heat generated within the compressor shell is usually
due to:
1. High amperage.
2. Low refrigerant charge.
3. Frequent recycling.
4. Dirty condenser.
TERMINAL OVERLOAD - TEST
(Compressor - External Type)
1. Remove overload.
2. Allow time for overload to reset before attempting
to test.
3. Apply ohmmeter probes to terminals on overload
wires. There should be continuity through the overload.
TERMINAL OVERLOAD (Internal)
1.With no power to unit, remove the leads from the
compressor terminals.
2.Using an ohmmeter, test continuity between terminals C-S and C-R. If not continuous, the compressor overload is open and the compressor must be
replaced.
FAN MOTOR
A single phase permanent split capacitor motor is
used to drive the evaporator blower and condenser
fan. A self-resetting overload is located inside the
motor to protect against high temperature and high
amperage conditions.
FAN MOTOR - TEST
1.Determine that capacitor is serviceable.
Some model compressors are equipped with an internal
overload. The overload is embedded in the motor windings to sense the winding temperature and/or current
draw. The overload is connected in series with the common motor terminal.
2.Disconnect fan motor wires from fan speed switch
or system switch.
3.Apply "live" test cord probes on black wire and common terminal of capacitor. Motor should run at high
speed.
Page 17
Figure 5: Fan Motor
4. Apply "live" test cord probes on red wire and
common terminal of capacitor. Motor should run
at low speed.
5. Apply "live" test cord probes on each of the
remaining wires from the speed switch or system
switch to test intermediate speeds.
CAPACITOR, RUN
A run capacitor is wired across the auxiliary and main
winding of a single phase permanent split capacitor motor
such as the compressor and fan motor. A single capacitor
can be used for each motor or a dual rated capacitor can
be used for both.
The capacitor's primary function is to reduce the line
current while greatly improving the torque characteristics
of a motor. The capacitor also reduces the line current to
the motor by improving the power factor of the load. The
line side of the capacitor is marked with a red dot and is
wired to the line side of the circuit (see Figure 6.)
CAPACITOR - TEST
1. Remove capacitor from unit.
2. Check for visual damage such as bulges, cracks, or
leaks.
3. For dual rated, apply an ohmmeter lead to common
(C) terminal and the other probe to the compressor
(HERM) terminal. A satisfactory capacitor will cause
a deflection on the pointer, then gradually move back
to infinity.
4. Reverse the leads of the probe and momentarily
touch the capacitor terminals. The deflection of the
pointer should be two times that of the first check if
the capacitor is good.
5. Repeat steps 3 and 4 to check fan motor capacitor.
NOTE: A shorted capacitor will indicate a low resistance
and the pointer will move to the "0" end of the
scale and remain there as long as the probes
are connected.
An open capacitor will show no movement of
the pointer when placed across the terminals of
the capacitor.
SYSTEM CONTROL SWITCH
(Heat Pump & Electric Heat Models)
An eight position control switch is used to regulate the
operation of the fan motor and compressor. The
compressor can be operated with the fan operating at
low, medium or high speed in the cooling or heating mode.
The fan motor can also be operated independently on
medium speed. See switch section as indicated on
decorative control panel (see Figure 7.)
Figure 6: RUN CAPACITOR HOOK-UP
Page 18
1. "Off" Position - everything is off.
2. "Lo Cool" Position - fan operates on low speed,
compressor is on.
3. "Med Cool" Position - fan operates on medium speed,
compressor is on.
4. "Hi Cool" Position - fan operates on high speed,
compressor is on.
5. "Hi Heat" Position - fan operates on high speed,
compressor or electric heater is on.
6. "Med Heat" Position - fan operates on medium speed,
compressor or electric heater is on.
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