Heat Load Form .......................................................................................................................................8
Heating Load Form Friedrich Unit Heat Pumps .......................................................................................9
Fan Motor................................................................................................................................................17
Capacitor, Run ........................................................................................................................................18
System Control Switch (Heat Pump & Electric Heat Models) ................................................................. 18
Heat Element ..........................................................................................................................................21
Drain Pan Valve.......................................................................................................................................22
"YS" - "YM" - "YL” Series Parts List.........................................................................................................39
“ES" - "EM” Series Pa rts List .................................................................................................................. 46
“EL” Series Parts List...............................................................................................................................51
“EK” Series Parts List..............................................................................................................................56
TTJ-0197 (1/97)(Page 3 of 64)
FRIEDRICH ROOM MODEL NUMBER CODE
1st DIGIT - FUNCTION
S = Straight Cool, Value Series
C = Straight Cool, Budget Series
Y = Heat Pump
E = Electric Stri p
K = Straight Cool, Challenger Series
W = Thru-The-W all, W allMaster Series
2nd DIGIT - TYPE
C = Casement
P = PowerMiser “Po rtable”
Q = QStar
S = Small Chassis
M = Medium Chassis
L = Large Chassis
W = Built-In
H = Hazardgard
3rd & 4th DIGITS - APPROXIMATE BTU/HR (Cooling)
Heating BTU/HR capacity listed in Specifications/Performance Data Section
ES15H33A
5th DIGIT - ALPHABETICAL MODIFIER
6th DIGIT - VOLTAGE
In the application and sizing of room air conditioners for cooling, it is most important to give full consideration to all
factors which ma y contribute to the heat loss or gain of the space to be conditioned. It is therefore necessary to make
a survey of the space to be conditioned and calculate the load requirements before a selection of the size of the
equipment needed can be made.
The load requirement may be determined very easily by simply using the standard “AHAM” Load Calculating Form,
on Page 7. This f orm is very easy to use and is self explanatory throughout. It is necessary only to insert the proper
measurements on the lines provided and multiply by the given factors, then add the result for the total load requirements.
Cooling load requirements are generally based on the cooling load for comfortable air conditioning which does not
require specific conditions of inside temperature and humidity. The load calculation form is based on outside design
temperature of 95° FDB and 75° FWB. It can be used f or areas in the Continental United States having other outside
design temperatures by applying a correction factor for the particular locality as determined from the map shown on
Page 6.
When sizing a TwinTemp unit for cooling and heating, we must remember that the heating capacity of any given unit
varies directly with the outdoor ambient temperature. Also, we must keep in mind the average low temperatures
which might be experienced in the locality where the unit is to be installed. Theref ore, when sizing a TwinTemp unit,
both cooling and heating requirements must be calculated. Do not oversize, or undersize, one phase of the unit’s
capacity at the expense of the other . In those cases where the unit will provide satisfactory cooling at all times b ut will
be inadequate for those few times that the outdoor temperature is below the maximum low for the unit, additional
auxiliary heating facilities must be provided to insure that adequate heat is available at all times.
TTJ-0197 (1/97)(Page 5 of 64)
INSTRUCTIONS FOR USING COOLING LOAD ESTIMATE
FORM FOR ROOM AIR CONDITIONERS
(AHAM PUB. NO. RAC-1)
A.This cooling load estimate form is suitable for estimating the cooling load for comfo rt air conditioning installa-
tions which do not require specific conditions of inside temperature and humidity.
B.The form is based on an outside design temperature of 95°F dry bulb and 75°F wet bulb. It can be used for
areas in the continental United States having other outside design temperatures b y applying a correction f actor
for the particular locality as deter mined from the map.
C.The form includes “day” factors for calculating cooling loads in rooms where da ytime comf ort is desired (such as
living rooms, offices, etc.)
D.The numbers of the following paragraphs refer to the corresponding numbered item on the form:
1.Multiply the square feet of window area for each e xposure by the applicable factor. The window area is the
area of the wall opening in which the window is installed. F or windows shaded by inside shades or v enetian
blinds, use the factor for “Inside Shades.” For windows shaded by outside awnings or by both outside
awnings and inside shades (or venetian blinds), use the factor for “Outside Awnings.” “Single Glass”
includes all types of single thickness window s, and “Double Glass” includes sealed airspace types, storm
windows, and glass b lock. Only one n umber should be entered in the right hand column for Item 1, and this
number should represent only the exposure with the largest load.
2.Multiply the total square feet of all windows in the room by the applicable factor.
3a.Multiply the total length (linear feet) of all walls exposed to the outside by the applicable factor. Doors
should be considered as being part of the wall. Outside walls facing due north should be calculated
separately from outside walls facing other directions. Walls which are permanently shaded by adjacent
structures should be considered “North Exposure.” Do not consider trees and shr ubbery as providing
permanent shading. An un-insulated frame wall or a masonry wall 8 inches or less in thickness is considered “Light Constr uction.” An insulated wall or masonry wall over 8 inches in thickness is considered
“Heavy Construction.”
3b.Multiply the total length (linear feet) of all inside walls between the space to be conditioned and any
unconditioned spaces by the given f actor. Do not include inside walls which separate other air conditioned
rooms.
4.Multiply the total square feet of roof or ceiling area by the factor given for the type of construction most
nearly describing the particular application (use one line only.)
5.Multiply the total square feet of floor area by the factor given. Disregard this item if the floor is directly on
the ground or over a basement.
6.Multiply the number of people who normally occupy the space to be air conditioned by the factor given.
Use a minimum of 2 people.
7.Determine the total number of watts for light and electrical equipment, except the air conditioner itself , that
will be in use when the room air conditioning is operating. Multiply the total wattage by the factor given.
8.Multiply the total width (linear feet) of any doors or arches which are continually open to an unconditioned
space by the applicable factor.
NOTE: Where the width of the doors or arches is more than 5 feet, the actual load may exceed the
calculated value. In such cases, both adjoining rooms should be considered as a single large room, and
the room air conditioner unit or units should be selected according to a calculation made on this new basis.
9.Total the loads estimated for the foregoing 8 items.
10.Multiply the subtotal obtained in item 9 by the proper correction factor, selected from the map, for the
particular locality. The result is the total estimated design cooling load in BTU per hour.
E.F or best results, a room air conditioner unit or units ha ving a cooling capacity rating (determined in accordance
with the NEMA Standards Publication for Room Air Conditioners, CN 1-1960) as close as possible to the
estimated load should be selected. In general, a greatly ov ersized unit which would oper ate intermittently will be
much less satisfactory than one which is slightly undersized and which w ould operate more nearly continuously.
F.Intermittent loads such as kitchen and laundry equipment are not included in this form.
(Page 6 of 64)TTJ-0197 (1/97)
COOLING LOAD ESTIMATE FORM
TTJ-0197 (1/97)(Page 7 of 64)
HEAT LOAD FORM
The heat load form, Page 9, may be used by servicing
personnel to determine the heat loss of a conditioned
space and the ambient winter design temperatures in
which the unit will heat the calculated space.
The upper half of the form is for computing the heat
loss of the space to be conditioned. It is necessary only
to insert the proper measurements on the lines provided and multiply by the given factors, then add this
result for the total heat loss in BTU/Hr./°F.
The BTU/Hr. per °F temperature difference is the 70°F
inside winter designed temperature minus the lowest
outdoor ambient winter temperature of the area where
the unit is installed. This temper ature diff erence is used
as the multiplier when calculating the heat loss.
The graph shows the following:
Left Hand ScaleUnit capacity BTU/Hr. or heat
loss BTU/Hr.
Bottom ScaleOutdoor ambient temperature,
base point.
Heat Pump ModelBTU/Hr. capacity heat pump will
deliver at outdoor temperatures .
Balance PointMaximum BTU/Hr. heat pump
will deliver at indicated ambient
temperature.
Below is an example using the heat load form:
A space to be conditioned is part of a house geographi-
cally located in an area where the lowest outdoor ambient winter temperature is 40°F. The calculated heat loss
is 184 BTU/Hr./°F.
Subtract 40°F (low est outdoor ambient temperature f or
the geographical location) from 70°F (inside design temperature of the unit) for a difference of 30°F. Multiply
184 by 30 for a 5500 BTU/Hr. total heat loss for the
calculated space.
On the graph, plot the base point (70°) and a point on
the 40°F line where it intersects with the 5500 BTU/Hr.
line on the left scale. Draw a straight line from the base
point 70 through the point plotted at 40°F. This is the
total heat loss line.
Knowing that we have a 5500 BTU/Hr. heat loss, and
we expect that our heat pump will maintain a 70°F inside temperature at 40°F outdoor ambient, we plot the
selected unit capacity BTU/Hr. of the unit between 35°
and 60° on the graph and draw a straight line between
these points. Where the total heat loss line and the unit
capacity line intersect, read down to the outdoor ambient temperature scale and find that this unit will deliver
the required BTU/Hr. capacity to approximately 30°F.
Net Weight113117141198
Shipping Weight124128153217
(Page 10 of 64)TTJ-0197 (1/97)
PERFORMANCEEV APORATOR AIROPERATINGELECTRICALR-22COMP.
DA T A*TEMP. °F.PRESSURESRATINGSREFRIG.OIL
CoolingDISCHARGETEMP .SUCTIONDISCHARGEAMPSLOCKEDCHARGE INCHARGE IN
Net Weight110121135191215108133
Shipping Weight121132147210234119145
(Page 12 of 64)TTJ-0197 (1/97)
PERFORMANCEEV APORATOR AIROPERATINGELECTRICALR-22COMP.
DA T A*TEMP. °F.PRESSURESRA TINGSREFRIG.OIL
CoolingDISCHARGETEMP .SUCTIONDISCHARGEAMPSLOCKEDCHARGE INCHARGE IN
STEP 1Before sliding chassis into outer shell, turn chassis on its side and add drain hole by drilling ½"
diameter hole as shown in Figure 1.
STEP 2DC-2 mounts to the bottom of the outer shell as shown in Figure 2 on the right side as you
face the unit. Use two (2) 10 - 24 x 3/8" long machine screws and 10 - 24 hex nuts provided.
STEP 3SQ, KQ, YQ Models - Drill two ¼" holes in outer shell as shown in Figure 3. Also drill a 3/8"
diameter hole in the base pan 3½" from the back and 3½" from right side.
STEP 4Small and Medium Chassis Models - Mount in second and third holes from the rear of shell;
See Figure 4.
STEP 5Large Chassis Models - Mount in third and fourth holes from the rear of shell; see Figure 5.
STEP 6Connect a suitable length of garden hose or other tubing to end of the drain tube to drain the
condensate away.
TTJ-0197 (1/97)(Page 15 of 64)
COMPONENTS OPERATION & TESTING
WARNING
DISCONNECT ELECTRICAL POWER TO
UNIT BEFORE SERVICING OR TESTING
COMPRESSORS
GROUND TEST
Use an ohmmeter set on its highest scale. Touch one
lead to the compressor body (clean point of contact as
a good connection is a must) and the other probe in
turn to each compressor terminal (see Figure 2.) If a
reading is obtained, the compressor is grounded and
must be replaced.
Compressors are single phase, 115 or 230/208 volt,
depending on the model unit. All compressor motors
are permanent split capacitor type using only a running
capacitor across the start and run terminal.
All compressors are internally spring mounted and externally mounted on rubber isolators.
COMPRESSOR WINDING TEST (See Figure 1)
Remove compressor terminal box cover and disconnect wires from terminals. Using an ohmmeter, check
continuity across the following:
1. Terminal “C” and “S” - no continuity - open winding - replace compressor.
2. Terminal “C” and “R” - no continuity - open winding - replace compressor.
3. Terminal “R” and “S” - no continuity - open winding - replace compressor.
Figure 2: Typical Ground Test
CHECKING COMPRESSOR EFFICIENCY
The reason for compressor inefficiency is normally due
to broken or damaged suction and/or discharge valves,
reducing the ability of the compressor to pump refrigerant gas.
This condition can be checked as follows:
1. Install a piercing valve on the suction and discharge or liquid process tube.
2. Attach gauges to the high and low sides of the
system.
3. Start the system and run a “cooling or heating
performance test.”
Figure 1:Compressor Winding Test
If test shows:
A. Below normal high side pressure.
B. Above normal low side pressure.
C. Low temperature difference across coil.
The compressor valves are faulty - replace the
compressor.
THERMAL OVERLOAD (External)
Some compressors are equipped with an external overload which is located in the compressor terminal box
adjacent to the compressor body (see Figure 3.)
(Page 16 of 64)TTJ-0197 (1/97)
The overload is wired in series with the common motor
terminal. The overload senses both major amperage
and compressor temperature. High motor temperature
or amperage heats the disc causing it to open and break
the circuit to the common motor terminal.
Figure 3: External Overload
Should the internal temperature and/or current draw become excessive, the contacts in the overload will open,
turning off the compressor. The overload will automatically reset, but may require several hours before the heat
is dissipated.
CHECKING THE INTERNAL OVERLOAD
(see Figure 4.)
Figure 4INTERNAL OVERLOAD
Heat generated within the compressor shell is usually
due to:
1. High amperage.
2. Low refrigerant charge.
3. Frequent recycling.
4. Dirty condenser.
TERMINAL OVERLOAD - TEST
(Compressor - External Type)
1. Remove overload.
2. Allow time for overload to reset before attempting to test.
3. Apply ohmmeter probes to terminals on overload
wires. There should be continuity through the
overload.
TERMINAL OVERLOAD (Internal)
1.With no power to unit, remove the leads from the
compressor terminals.
2.Using an ohmmeter, test continuity between terminals C-S and C-R. If not continuous, the compressor overload is open and the compressor must
be replaced.
FAN MOTOR
A single phase permanent split capacitor motor is
used to drive the evaporator blower and condenser
fan. A self-resetting overload is located inside the
motor to protect against high temperature and high
amperage conditions.
FAN MOTOR - TEST
1.Determine that capacitor is serviceable.
Some model compressors are equipped with an internal overload. The overload is embedded in the motor
windings to sense the winding temperature and/or current draw. The overload is connected in series with the
common motor terminal.
TTJ-0197 (1/97)(Page 17 of 64)
2.Disconnect fan motor wires from fan speed switch
or system switch.
3.Apply “live” test cord probes on black wire and
common terminal of capacitor. Motor should run
at high speed.
Figure 5: Fan Motor
4.Apply “live” test cord probes on red wire and common terminal of capacitor. Motor should run at
low speed.
5.Apply “live” test cord probes on each of the remaining wires from the speed switch or system
switch to test intermediate speeds.
CAPACI TOR, RUN
A run capacitor is wired across the auxiliary and main
winding of a single phase permanent split capacitor
motor such as the compressor and fan motor. A single
capacitor can be used for each motor or a dual rated
capacitor can be used for both.
The capacitor's primary function is to reduce the line
current while greatly improving the torque characteristics of a motor. The capacitor also reduces the line current to the motor by improving the power factor of the
load. The line side of the capacitor is marked with a red
dot and is wired to the line side of the circuit (see Figure 6.)
CAPACITOR - TEST
1. Remove capacitor from unit.
2. Check for visual damage such as bulges, cracks,
or leaks.
3. For dual rated, apply an ohmmeter lead to common (C) terminal and the other probe to the compressor (HERM) terminal. A satisfactory capacitor
will cause a deflection on the pointer, then gr adually move back to infinity.
4. Reverse the leads of the probe and momentarily
touch the capacitor terminals. The deflection of the
pointer should be two times that of the first check if
the capacitor is good.
5. Repeat steps 3 and 4 to check fan motor capacitor.
NOTE: A shorted capacitor will indicate a low resis-
tance and the pointer will move to the "0" end
of the scale and remain there as long as the
probes are connected.
An open capacitor will show no movement of
the pointer when placed across the terminals
of the capacitor.
SYSTEM CONTROL SWITCH
(Heat Pump & Electric Heat Models)
An eight position control switch is used to regulate the
operation of the fan motor and compressor. The compressor can be operated with the fan operating at low,
medium or high speed in the cooling or heating mode.
The fan motor can also be operated independently on
medium speed. See switch section as indicated on decorative control panel (see Figure 7.)
1. "Off" Position - ever ything is off.
Figure 6: RUN CAPACITOR HOOK-UP
(Page 18 of 64)TTJ-0197 (1/97)
2. "Lo Cool" Position - fan operates on low speed,
compressor is on.
3. "Med Cool" Position - fan operates on medium
speed, compressor is on.
4. "Hi Cool" Position - fan operates on high speed,
compressor is on.
5. "Hi Heat" Position - fan operates on high speed,
compressor or electric heater is on.
6. "Med Heat" Position - fan operates on medium
speed, compressor or electric heater is on.
Figure 7: SYSTEM CONTROL PANEL
(Heat Pump & Electric Heat Models)
SYSTEM CONTROL SWITCH - TEST
Disconnect leads from control switch. Turn control to
position being tested (see Figure 8.) There must be
continuity as follows:
1. "Off" Position - no continuity between terminals.
2. "Lo Cool" Position - between terminals "C" and "3",
"C2" and "2", "LO" and "M/S", "AR" and "5".
3. "Med Cool" Position - between terminals "C" and
"3", "C2" and "2", "M" and "M/S", "AR" and "5".
4. "Hi Cool" Position - between terminals "C" and "3",
"C2" and "2", "H" and "M/S", "AR" and "5".
5. "Hi Heat" Position - between terminals "C" and "1",
"C2" and "4", "H" and "M/S", "AR" and "5".
6. "Med Heat" Position - between terminals "C" and
"1", "C2" and "4", "M" and "M/S", "AR" and "5".
7. "Lo Cool" Position - between terminals "C" and "1",
"C2" and "4", "LO" and "M/S", "AR" and "5".
7. "Lo Heat" Position - fan operates on low speed,
compressor or electric heater is on.
8. "Fan Only" Position - operates on medium speed.
NOTE: Heat pump models with electric heat - in the
heat position, heating element only will be energized when outdoor temperature is below the
operating range of the heat pump.
Figure 8: SYSTEM CONTROL SWITCH
(Heat Pump & Electric Heat Models)
8. "Fan Only" Position - between terminals "L1" and
"M".
THERMOSTAT - (see Figure 9)
A cross ambient thermostat is used on all heat pump
and electric heat units. In addition to cycling the unit in
a heating or cooling operation, the thermostat will terminate the cooling cycle in the event ice forms on the
evaporator coil, in this case the thermostat functions
as a de-ice control. A resistor (anticipator) is positioned
Figure 9: THERMOSTAT
TTJ-0197 (1/97)(Page 19 of 64)
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