•Voltage Mode Operation With
Fixed 1.25V Output or Resistor
Adjustable Output
•Efficient BiCMOS Design
•Inherent Short Circuit Protection
BLOCK DIAGRAM
DESCRIPTION
The UCC3890 controller is optimized for use as an off-line, low power, low
voltage, regulated current supply, ideally suited for battery trickle charger
applications. The unique circuit topology used in this device can be visualized as two cascaded flyba ck converters; each operating in the discontinuous mode, and both driven from a s ingle external power switch. The
significant benefit of this approach is the ability to charge low voltage batteries in off-line applications with no transformer, and low internal losses.
The control algorithm used by the UCC3890 forces a switch on time inversely pr oportional to t he input line v oltage, whil e the switch off time is
inversely proportional to the output voltage. This action is automatically
controlled by an internal fe ed ba c k l oo p a nd reference. The cascaded c onfiguration al lows a large voltage c onversion ratio with r easonable switch
duty cycle.
While the UCC3890 is ideally suited for control of constant current battery
chargers, provision is also made to operate as a fixed 1.25V regulated
supply, or to use a resistor vo l tage di vi der to obtain output vol tages hi gher
than 1.25V.
Note: This device incorporates patented technology used under license from
Lead Temperature (Soldering, 10 sec.) . . . . . . . . . . . . . +300°C
Currents are positive into, negative out of the specified terminal.
Consult Packaging Section of Databook for thermal limitations
and considerations of packages.
ELECTRICAL CHARACTERISTICS:
UCC1890, –40°C to 85°C for the UCC2890, and 0°C to 70°C for the UCC3890. No load at DRIVE pin (C
Unless otherwise stated, these specifications apply for TA = –55°C to 125°C for
= 0), TA = TJ.
LOAD
PARAMETERTEST CONDITIONSMINTYPMAX UNITS
General
VDD Zener VoltageI
Minimum Operat in g C urre nt I
TON
= 4.75mA,I
DD
= 0mA8.39.09.4V
TON
IDD = –1mA, F = 150kHz1.652.0mA
Undervoltage Lockout
Minimum Voltage to StartFB = 07.88.69.2V
Minimum Voltage after StartFB = 05.756.36.65V
HysteresisFB = 01.82.32.6V
VDD – V
START
FB = 00.20.40.7V
Oscillator
AmplitudeI
TON
= 3mA; I
= 50µA; VFB = 0V CT = 100pF3.13.43.7V
TOFF
CT to DRIVE High DelayOverdrive = 200mV80200ns
CT to DRIVE Low DelayOverdrive = 200mV50100ns
Charge Coefficient I
CT/ITON
Discharge Coefficent I
CT/ITOFF
I
= 3mA; V
TON
I
= 50µA; VCT = 3.0V0.951.001.05µA/µA
TOFF
= 3.0V0.1350.150.165µA/µA
CT
Driver
V
OL
V
OH
Rise TimeC
Fall TimeC
I = 100mA (Note 1)0.71.8V
I = –100mA referred to VDD (Note 1)–2.9–1.5V
= 1nF3570ns
L
= 1nF3060ns
L
Line Voltage Detection
Minimum I
Detector Hysteresis110
TON
I
for Fault1.01.52.0mA
TON
On Time During Fault0.5
OUT
V
Error Amplifier
Reference LevelI
Voltage at TOFFI
Regulation gmI
= 50µA, ICT = 25µA, TJ = 25°C1.201.251.30V
TOFF
= 50µA, ICT = 25µA, Over Temperature1.151.251.35V
TOFF
I
= 50µA0.30.40.5V
TOFF
= 50µA (Note 2)2.04.07.7mA/V
TOFF
Current Sense Amplifier
GainVCS = 90 – 110mV11.812. 513.0V/V
Input Offset VoltageV
Input Voltage for CS Amplifier EnabledI
Input Voltage for CS Amplifier DisabledI
= 90 – 110mV–505mV
CS
= 3mA, Referred to VDD–1.5–0.8V
TON
= 3mA, Referred to VDD–0.8–0.3V
TON
µ
A
µ
s
Note 1: VDD forced to 100mV below VDD Zener Voltage
∆
CT
Note 2: gm is defined as
are for I
at 65% amd 35% of its maximum value.
CT
I
for the values of VFB where the error amp is in regulation. The two points used to calculate gm
∆
FB
V
2
Page 3
PIN DESCRIPTIONS
CS:
The high side of the current sense shunt is connected to this pi n. Short CS to VDD for voltage feedback
operation.
UCC1890
UCC2890
UCC3890
TOFF:
Resistor R
this pin to provide a maximum capacitor discharge current proportional to output voltage.
OFF
connects from voltage output to
CT:
Oscillator timing capacitor is connected to this pin.
DRIVE:
FB:
Gate drive to external power switch.
Output of current sense amplifier. This pin can be
used for direct output voltage feedback if the current
sense amp input pin CS is shorted to the VDD pin.
GND:
Ground pin.
APPLICATION INFORMATION
TON:
Resistor R
ON
connects f rom lin e in put to this pin to
provide capacitor charge current proportional to line voltage. The current in R
ON
also provides power for the 9V
shunt regulator at VDD.
VDD:
Output of 9V shunt regulator.
Figure 1. Typical Voltage Mode Application
OPERATION (VOLTAGE OUTPUT)
Figure 1 shows a typical voltage mode application.
When input voltage is first applied, all of the current
through R
DD
and 80% of the current through R
ON,
charge the ext ernal ca paci tor C3 conn ected to VDD. As
the volta ge builds on VDD, u ndervoltage lockout holds
the circuit off and the output DRIVE low until VDD
reaches 8.4 V. At this time, DRI VE go es h igh, turning on
the external power switch Q1, and 15% of the current
into TON is directed to the timing capacitor C
T
. The voltage at TON is fixed at approximately 11V, so C
charges to a fixed threshold with current
IN
V
I = 0.2 •
– 11V
ON
R
Since the input line is much greater than 11V, the
charge current is approximately proportional to the input
T
line voltage. DRIVE is only high while C
is charging, so
the power swi tc h on time i s inver sely pr oportional to l ine
voltage. Thi s provides a constant line voltage-switch on
time product.
At the end of the switc h on time, Q1 i s turned off, and
ON
the 15% of the R
current which was charging CT is
diverted to ground . The power switch off time is controlled by discharge of C
T
, which is determined by the outut
voltage as described here:
T
3
UDG-96053
UDG-96054
Page 4
APPLICATION INFORMATION (cont.)
1. When V
provides inherent short circuit protection. However,
to ensure output voltage startup when the output is
not a short, a high value resistor, R
parallel with C
frequency.
OUT
= 0, the off time is infinite. This feature
S,
is placed in
T
to establish a minimum switching
Frequency =
TON =
TOFF
CT • 3.4V
(
)
MAX
= 1.5 • RS • CT (regions 1 and 4
TON
IN
V
1
+
TOFF
•
0.15 • R
– 11V
UCC1890
UCC2890
UCC3890
ON
)
2. As V
set by R
As V
OUT
rises above approximately 0.4V, I
OFF
, and is defined by
OUT
– 0.4V
DCHG
I
OUT
V
=
OFF
R
increases, I
DCHG
increases resulting in the
DCHG
is
reduction o f off time. The frequency of operation increases and V
OUT
rises quickly to its regulated
value.
3. In this regi on, a transconductance amplifier reduces
DCHG
I
in order to maintain V
OUT
in regulation. The
input to the transconduct an ce am plif ier is the pin FB .
(In this mod e the pi n CS s hould be shorted to VDD.)
FB can either be connected directly to V
late at nominal V
OUT
V
through a resistor divider R
OUT
= 1.25V or to be connected to
OUT
VS1/RVS2
to regu-
to regu-
late at nominal
)
+
VS2
R
DCHG
4. If V
•
VS1
1.25V
OUT
V
=
OUT
should ri se above its regulation range, I
(R
R
VS2
falls to zero and the circuit returns to the minimum
frequency established by R
S
and CT.
The range of sw itch ing fre quencies is establis hed by
ON
R
OFF
, R
, RS, and CT as follows:
TOFF
•
CT
=
V
3.4V
OUT
•
R
− 0.4V
OFF
(region 2
)
The above equ ations assume VD D = 9, the voltage
at TON = 11V, the voltage at TOFF = 0.4V.
OPERATION (CURRENT OUTPUT)
Figure 2 shows a typical current mode application. In
current mode, operation is the same as in voltage
mode, except that in region 3 the transconductance amplifier is cont rolled by the current sense a mplifier which
SH
senses the voltage across a shunt resistor R
. The circuit then re gulates the curre nt in the shunt to the nominal value
100mV
SH
I
=
SH
R
The circuit shown in this schematic would be suitable
for an application which trickle charges a battery at a
low current, (e.g. C/10), and has a battery load which
draws a high current, (e.g. C), when turned on. In that
SH1
case, R
100mV
value is chosen so that
C
=
SH1
R
10
Figure 2. Typical Current Mode Applicatio n
4
UDG-96055
Page 5
APPLICATION INFORMATION (cont.)
SH2
If R
then the regulator output will assist the battery, minimizing or eliminating battery output current.
DESIGN EXAMPLE
A typical design has the following requirements:
V
V
V
I
F
η
Component v alu es a re in dica ted i n Figure 3. The explanation for the choices in component values follows.
First calc ulate the maximum duty cycle, d(max). To calculate thi s assume that at m aximum loa d/minimum line
conditions, the converter wil l be at the continuous conduction bou nd ary and there wil l be no i dle time after the
inductors are discharged. Fo r all other load/line conditions, the UCC3890 will stretch the off time, to create an
idle time afte r the inductors are discharged, in order to
is chosen so that
100mV
IN
OUT
OUT
LOAD
SWITCHING
(eff.)=50% (excluding efficiency losses in
=
SH2
R
′
C
=80 to 132 VAC or 100 to 180 VDC
=1.25V
=2.0V (assumes 1.25
750mV forward drop in D3)
=500mADC max
=100kHz
D3 which will be very large due to the
low output voltage. Losses in D3 are
accounted for by using V
calculations).
VOUT
with
OUT
′
in the
UCC1890
UCC2890
UCC3890
maintain a con stant out put volt age. For a single flyback
stage at continuous conduction boundary
1 +
1
V
OUT
V
IN
1 +
1 +
F
100kHz
1
IN
V
√
OUT
V
1
100V
√
2V
d(max
SWITCHING
0.125
1 − 0.125
100kHz
′
= 0.125
)
=
1.25
= 8.75µs
µ
s
d =
For the cascaded flyback stages of the UCC3890 topology, the corresponding equation is
d(max) =
in this case
d(max) =
Next using the operating frequency and the maximum
duty cycle to calculate the maximum on time
TON(max) =
in this case
TON(max) =
correspondingly
TOFF(min) =
Figure 3. Example Application
5
UDG-96056
Page 6
APPLICATION INFORMATION (cont.)
The average input current at minimum line and maximum load will be
UCC1890
UCC2890
UCC3890
entire range of operat ion mus t be cons idered to choose
values for the rest of the components.
′
OUT
V
OUT
I
IN
I
=
•
IN
V
η
in this case
I
IN
500mA
=
0.5
•
2V
100V
=
20mA
Knowing that input current is drawn from the line only
during TON, calculate the peak current in L1 to be
L1
I
(pk) =
2
•
IIN •
TON + TOFF
TON
in this case
L1
I
(pk) =
2
•
20mA •
1.25
+ 8.75µs
µ
1.25
s
= 320mA
µ
s
Now calculate the value for L1
=
VIN
•
(pk)
L1
I
1
L
TON
in this case
1
L
= 100V •
1.25µs
320mA
= 390µH
The output voltage of the first flyback stage is
C1
V
= VIN •
TON
TOFF
in this case
C1
V
= 100V •
1.25µs
8.75µs
= 14.3V
Knowing that out put cur rent is pro vi ded to t he l oad only
during TOFF, calc ulate the peak current in L2 to be
L2
I
(pk) =
2
OUT
•
TON
•
I
TOFF
TOFF
+
in this case
L2
I
(pk) =
2
•
0.5A •
Now calculate the value of L
′ •
OUT
L2 =
V
I
1.25µs + 8.75µs
TOFF
(pk)
L2
8.75
2
s
= 1.14A
µ
in this case
2
L
= 2V •
8.75µs
1.14A
= 15µH
For all of the calculations so far only the maximum
load/minimum line condition have been considered. The
Under all no rmal operating c onditions the current I
TON,
(which is the current in RON), should be greater than
2mA and less than 7 .5mA. In this case set R
TON
I
= 2.8mA at low line. The voltage at TON will be
ON
to give
about 11V so
−
100V
ON
R
=
With RON = 33k, I
180V − 11V
TON
I
=
At high line, the power dissipation in R
)
ON
P(R
ON
R
will need to be at least a 1W resistor. Alternately it
2.8mA
= (
180V
33k
11V
TON
at high line will be
=
33k
Ω
= 5.1mA
−
11V) • 5.1mA = 860mW
ON
will be
could be four 1/4W 8.2kΩ resistors in series.
Once R
for C
ON
is set, CT can be chos en. The char ge current
T
is nominally 15% of I
TON
, and the nominal oscilla-
tor amplitude is 3.4V, so
TON =
CT • 3.4V
•
0.15
TON
I
solving for CT
TON • 0.15 • I
CT =
TON
I
at low line is 2.8m A , an d th e ta rge t TON at low line
3.4V
TON
is 1.25µs, so in this case
•
1.25µs
CT =
The final com pone nt to be chosen is R
0.15 • 2.8mA
3.4V
= 150pF
OFF
, which determines the minimum value of TOFF. When the output
voltage is bel ow the regu lation point, the discharge current for CT is equal to I
TOFF
(the current in R
OFF
). Un-
der that condition
TOFF =
CT • 3.4V
TOFF
I
since the voltage at the TOFF pin = 0.4V
−
OUT
OFF
R
OFF
• (
CT
0.4V
OUT
V
•
−
3.4V
0.4V
OFF
)
V
TOFF
I
=
substituting and solving for R
T
OFF
R
=
The largest discharge current, and hence the minimum
off time, will occur when the output is about 10mV be-
6
Page 7
APPLICATION INFORMATION (cont.)
low the regulation point of 1.25V. The minimum value
for TOFF is 8.75µs. So in this case
−
)
8.75µs • (1.24V
OFF
R
=
150pF • 3.4V
OTHER APPLICATION CONSIDERATIONS
Output Capacitor:
For best regulation of the output
voltage or c urrent, the output capacitor should be a low
ESR type. This i s e spec ial ly t rue when operating i n current sense mode with a non-linear load such as a battery. If a low ESR cap acitor cannot be used, excellent
regulation can also be achi eved by placing a low pass
R/C filter between the current shunt and the CS input.
No Load Operation:
tected for short circui ts, but not for open circuits. If the
load is removed, the output voltage will quickly rise up
to the regulation point. Once the output is above the
regulation voltage, the oscillator will drop to the minimum frequency set by R
put, even at this low frequency the output voltage can
quickly rise to a dangerous le vel. To protect agains t t h is ,
it is recom mended that a zene r or other voltage clamp
always be connected across the output. The clamp
should be chosen to be above the normal range of output voltage, but low enough to protect the output capacitor. In current sense operation, removal of the load
will also break the regulation loop, in which case a sim-
0.4V
= 15k
The UCC3890 is inherently pro-
S/CT
. With no loa d on the out-
UCC1890
UCC2890
UCC3890
ple clamp on the output may not be adequate. In current
sense mode it is recomme nded tha t a second z ener be
connected from the out pu t to the FB pi n, the br eakdown
voltage of this clamp c hosen to b e high enough so that
it will not conduct during normal operation, but will conduct at least 2V lower than the breakdown voltage of
the other clamp.
Gate Drive for the External FET:
guaranteed to be able to deliver at least 1mA of steady
state curre nt to the gate of the external FET at I
2mA. If I
TON
is higher th an 2mA, 80% of the additional
current is available to drive the FET gate. If, as in the
design example above, a moderate sized FET such as
the IRF820 i s used, the operating frequency is 100kHz,
and the minimum I
TON
at low line is 2.8mA, then the
available gate drive current may be adequate. The
IRF820 needs about 13nC to ch arge the gate on ea ch
cycle. At 100kHz, this is equivalent to 1.3mA steady
state; below the minimum 1.64mA available. In some
combinations of a larger FET, and/or higher frequency
operation, t he current available for dri ving the gate may
not be adequa te. In t hat ca se ex tra current may be provided by connecting a resistor R
the VDD pin. This resistor should be sized so that under
all conditions the current input to VDD is below the
7.5mA absolute maximum limit. R
be a power resistor.
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any product or service without notice, and advise customers to obtain the latest version of relevant information
to verify, before placing orders, that information being relied on is current and complete. All products are sold
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pertaining to warranty, patent infringement, and limitation of liability.
TI warrants performance of its semiconductor products to the specifications applicable at the time of sale in
accordance with TI’s standard warranty. Testing and other quality control techniques are utilized to the extent
TI deems necessary to support this warranty . Specific testing of all parameters of each device is not necessarily
performed, except those mandated by government requirements.
CERTAIN APPLICA TIONS USING SEMICONDUCT OR PRODUCTS MAY INVOLVE POTENTIAL RISKS OF
DEATH, PERSONAL INJURY, OR SEVERE PROPERTY OR ENVIRONMENTAL DAMAGE (“CRITICAL
APPLICATIONS”). TI SEMICONDUCTOR PRODUCTS ARE NOT DESIGNED, AUTHORIZED, OR
WARRANTED TO BE SUITABLE FOR USE IN LIFE-SUPPORT DEVICES OR SYSTEMS OR OTHER
CRITICAL APPLICA TIONS. INCLUSION OF TI PRODUCTS IN SUCH APPLICATIONS IS UNDERST OOD TO
BE FULLY AT THE CUSTOMER’S RISK.
In order to minimize risks associated with the customer’s applications, adequate design and operating
safeguards must be provided by the customer to minimize inherent or procedural hazards.
TI assumes no liability for applications assistance or customer product design. TI does not warrant or represent
that any license, either express or implied, is granted under any patent right, copyright, mask work right, or other
intellectual property right of TI covering or relating to any combination, machine, or process in which such
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party’s products or services does not constitute TI’s approval, warranty or endorsement thereof.
Copyright 1999, Texas Instruments Incorporated
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